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M16-32

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Re: M16-32  [#permalink]

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New post 23 Sep 2018, 20:50
kanthaliya wrote:
Bunuel wrote:
If \(a\) and \(b\) are positive, \(\frac{a}{b}\) is what percent of \(ab\)?


(1) \(|b - 2| = 4\)

(2) \(b^2 - 3b - 18 = 0\)



Hi Experts,

I have understood the solution but I have a small doubt. If in the question it is not given that a and b are positive.
then byStatement:1 b has 6 or -2 and Statement :2 has 6 and -3.
So could we take the common value of the solution hence answer C or we will prefer answer E ?


C would be the answer in this case, because after combining we'd get that b = 6 only.
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Re: M16-32  [#permalink]

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New post 30 Oct 2018, 14:43
Dear all ..
I don't think there is enough clarity about the number ab . I consider ab as a 2 digit number that is 10a+b .
But in the solution it is considered as a*b . I don't think so it is a good question as there is no clarity on this .
So please clarify on this . Thank you ^^
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Re: M16-32  [#permalink]

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New post 30 Oct 2018, 22:44
chipsy wrote:
Dear all ..
I don't think there is enough clarity about the number ab . I consider ab as a 2 digit number that is 10a+b .
But in the solution it is considered as a*b . I don't think so it is a good question as there is no clarity on this .
So please clarify on this . Thank you ^^


If it were a two-digit number it would have been explicitly mentioned. ab is a*b, recall that only * sign could be omitted.
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Re: M16-32   [#permalink] 30 Oct 2018, 22:44

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M16-32

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