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# M18 Q6

Author Message
Intern
Joined: 09 Sep 2010
Posts: 12

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07 Oct 2010, 12:57
Team A, team B, team C, and team D take part in a tournament in which every team plays once with each of its opponents. 3 points are awarded for victory, 1 for a draw, and 0 for defeat. The scoring table currently is as follows:

Team B: 7 points;
Team C: 4 points;
Team A: 0 points;
Team D: 0 points;

How many games are yet to be played in the tournament?

A. 0
B. 1
C. 2
D. 3
E. It cannot be determined from the information given

SOLUTION
[Reveal] Spoiler:
Team B has played all of its three matches - it could not have accumulated 7 points in 2 games. Also, because team A and team D have no points, team B tied with team C. Therefore team C beat either team A or team D. In either case, two games are yet to be played: A-D and D-C (or A-C).

MY ISSUE:
[Reveal] Spoiler:
Clearly the total no. of games is 3! i.e. 6 games
Then the total no. of points is 11 :-

Matches Pts Total
2 3 6 - Won (team B)
1 3 1 - Draw (team B)
1 3 3 -Won (team C)
1 1 1 - Draw (Team C)

So total no. of matches played : 5

Thus, 6 games to be played (-) 5 games played = 1 game remaining.

How come 2 matches remaining? Where am I wrong, pls help !!!
Senior Manager
Joined: 30 Aug 2009
Posts: 287
Location: India
Concentration: General Management

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07 Oct 2010, 16:06
sandhyash wrote:
Team A, team B, team C, and team D take part in a tournament in which every team plays once with each of its opponents. 3 points are awarded for victory, 1 for a draw, and 0 for defeat. The scoring table currently is as follows:

team B 7 points
team C 4 points
team A 0 points
team D 0 points
How many games are yet to be played in the tournament?

0
1
2
3
it cannot be determined from the information given
Team B has played all of its three matches - it could not have accumulated 7 points in 2 games. Also, because team A and team D have no points, team B tied with team C. Therefore team C beat either team A or team D. In either case, two games are yet to be played: A-D and D-C (or A-C).

MY ISSUE :

Clearly the total no. of games is 3! i.e. 6 games
Then the total no. of points is 11 :-

Matches Pts Total
2 3 6 - Won (team B)
1 3 1 - Draw (team B)
1 3 3 -Won (team C)
1 1 1 - Draw (Team C)

So total no. of matches played : 5

Thus, 6 games to be played (-) 5 games played = 1 game remaining.

How come 2 matches remaining? Where am I wrong, pls help !!!

B played 3 games (2 win and 1 draw) and C played 2 games ( 1 win and 1 draw)
the drawn game is b/w B and C so matches left are b/w A and D and b/w C and A or D
Retired Moderator
Joined: 02 Sep 2010
Posts: 803
Location: London

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07 Oct 2010, 16:38
sandhyash wrote:
Team A, team B, team C, and team D take part in a tournament in which every team plays once with each of its opponents. 3 points are awarded for victory, 1 for a draw, and 0 for defeat. The scoring table currently is as follows:

team B 7 points
team C 4 points
team A 0 points
team D 0 points
How many games are yet to be played in the tournament?

0
1
2
3
it cannot be determined from the information given
Team B has played all of its three matches - it could not have accumulated 7 points in 2 games. Also, because team A and team D have no points, team B tied with team C. Therefore team C beat either team A or team D. In either case, two games are yet to be played: A-D and D-C (or A-C).

MY ISSUE :

Clearly the total no. of games is 3! i.e. 6 games
Then the total no. of points is 11 :-

Matches Pts Total
2 3 6 - Won (team B)
1 3 1 - Draw (team B)
1 3 3 -Won (team C)
1 1 1 - Draw (Team C)

So total no. of matches played : 5

Thus, 6 games to be played (-) 5 games played = 1 game remaining.

How come 2 matches remaining? Where am I wrong, pls help !!!

There is only 1 draw.
In a draw both teams get 1 point
You are double counting that
_________________
Intern
Joined: 09 Sep 2010
Posts: 12

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08 Oct 2010, 08:14
Oh !!! I really was double counting the "Draw" match. Thanks a lot !!
VP
Status: Been a long time guys...
Joined: 03 Feb 2011
Posts: 1381
Location: United States (NY)
Concentration: Finance, Marketing
GPA: 3.75

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10 Jan 2013, 11:22
Bunuel.
What should be the average time to be spent on this question. On the practice test, I took 3 minutes plus got it wrong.
After careful reviewing, I understood this one. Do these types actually appear on the real thing?
Regards.
_________________
Manager
Joined: 18 Oct 2011
Posts: 90
Location: United States
Concentration: Entrepreneurship, Marketing
GMAT Date: 01-30-2013
GPA: 3.3

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10 Jan 2013, 11:36
Pretty Straight forward..
If B has 7 points and C has 4 points and A & D have 0 points then B and C each played a draw game. That leaves 2 wins for B and 1 win for C to add up their total. Since there are 6 total games possible 6-4 = 2 games left to play.
Intern
Joined: 09 Nov 2013
Posts: 11

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16 Nov 2013, 03:36
Was doing this question and got it wrong. If team B got Win+Win+Draw and team C got Win+Draw+Lost or Win+Draw+No game it got 4 points in both cases, but in 1st case it lost bo B, but in other it didnt play a game. So we 2 cases: B plays vs anyone but C 2 to get a win and gets a draw with C, OR it could win a game vs C once, won a game vs someone else, and draw with C. So we have 2 different numbers of games left. Am I wrong?
Re: M18 Q6   [#permalink] 16 Nov 2013, 03:36
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# M18 Q6

Moderator: Bunuel

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