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M20-03

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Bunuel
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M20-03 [#permalink] New post   16 Sep 2014, 01:07
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If two excavators, both working at the same constant rate, can dig a 10-meter-long trench in 50 minutes, how long will it take three same type excavators to dig a 15-meter-long trench?

A. 45 minutes
B. 50 minutes
C. 52 minutes
D. 54 minutes
E. 60 minutes
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B
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Bunuel
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Re M20-03 [#permalink] New post   16 Sep 2014, 01:07
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If two excavators, both working at the same constant rate, can dig a 10-meter-long trench in 50 minutes, how long will it take three same type excavators to dig a 15-meter-long trench?

A. 45 minutes
B. 50 minutes
C. 52 minutes
D. 54 minutes
E. 60 minutes


A single excavator can dig a 10-meter-long trench in 50*2 = 100 minutes. Therefore, it would take 100*1.5 = 150 minutes to dig a 15-meter-long trench.

Consequently, three excavators working together can complete a 15-meter-long trench in \(\frac{150}{3}=50\) minutes.


Answer: B
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Bunuel
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Re: M20-03 [#permalink] New post   19 Oct 2023, 14:20
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Soj1998
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Re: M20-03 [#permalink] New post   23 Jan 2024, 06:54
Hi Bunuel,
Could you please give a proper explanation for this question? How is one excavator working in 100 minutes? how did we get 50*2?
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Bunuel
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Re: M20-03 [#permalink] New post   23 Jan 2024, 07:30
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Soj1998 wrote:
Hi Bunuel,
Could you please give a proper explanation for this question? How is one excavator working in 100 minutes? how did we get 50*2?


The proper explanation is already given in the original post.

To answer your question: If two excavators working together can complete the task in 50 minutes, one excavator, working alone, would take twice as long, which is 100 minutes.
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Re: M20-03 [#permalink]
23 Jan 2024, 07:30
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