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M21-16

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Director
Status: Gonna rock this time!!!
Joined: 22 Jul 2012
Posts: 505

Kudos [?]: 72 [0], given: 562

Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE: Information Technology (Computer Software)

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10 Feb 2013, 03:27
1 gives us
y=0 or y=1

2 gives us the same.

Had 2 resulted in y=0 or y=2, would the answer have been C? cause y=0 is common in both statements ?
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hope is a good thing, maybe the best of things. And no good thing ever dies.

Who says you need a 700 ?Check this out : http://gmatclub.com/forum/who-says-you-need-a-149706.html#p1201595

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Kudos [?]: 72 [0], given: 562

Math Expert
Joined: 02 Sep 2009
Posts: 42583

Kudos [?]: 135518 [0], given: 12697

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10 Feb 2013, 03:35
Sachin9 wrote:
1 gives us
y=0 or y=1

2 gives us the same.

Had 2 resulted in y=0 or y=2, would the answer have been C? cause y=0 is common in both statements ?

What is the value of $$y$$?

(1) $$y^3+2y=y+2y^2$$. Rearrange and factor out $$y$$ to get $$y(y^2-2y+1)=0$$, which is the same as $$y(y-1)^2=0$$, so $$y=0$$ or $$y=1$$. Not sufficient.

(2) $$y^2=y$$. The same two solutions: $$y=0$$ or $$y=1$$. Not sufficient.

(1)+(2) Nothing new. Not sufficient.

As for your question: if from (2) we had that y=0 or y=2, then the answer would be C: y=0.
_________________

Kudos [?]: 135518 [0], given: 12697

Director
Status: Gonna rock this time!!!
Joined: 22 Jul 2012
Posts: 505

Kudos [?]: 72 [0], given: 562

Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE: Information Technology (Computer Software)

Show Tags

10 Feb 2013, 03:58
Bunuel wrote:
Sachin9 wrote:
1 gives us
y=0 or y=1

2 gives us the same.

Had 2 resulted in y=0 or y=2, would the answer have been C? cause y=0 is common in both statements ?

What is the value of $$y$$?

(1) $$y^3+2y=y+2y^2$$. Rearrange and factor out $$y$$ to get $$y(y^2-2y+1)=0$$, which is the same as $$y(y-1)^2=0$$, so $$y=0$$ or $$y=1$$. Not sufficient.

(2) $$y^2=y$$. The same two solutions: $$y=0$$ or $$y=1$$. Not sufficient.

(1)+(2) Nothing new. Not sufficient.

As for your question: if from (2) we had that y=0 or y=2, then the answer would be C: y=0.

Sorry Sir, Will adhere to rule 6 going forward.

Had 2 resulted in y=3 or y=4, answer would have been E ?
_________________

hope is a good thing, maybe the best of things. And no good thing ever dies.

Who says you need a 700 ?Check this out : http://gmatclub.com/forum/who-says-you-need-a-149706.html#p1201595

My GMAT Journey : http://gmatclub.com/forum/end-of-my-gmat-journey-149328.html#p1197992

Kudos [?]: 72 [0], given: 562

Math Expert
Joined: 02 Sep 2009
Posts: 42583

Kudos [?]: 135518 [1], given: 12697

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10 Feb 2013, 04:04
1
KUDOS
Expert's post
Sachin9 wrote:
Bunuel wrote:
Sachin9 wrote:
1 gives us
y=0 or y=1

2 gives us the same.

Had 2 resulted in y=0 or y=2, would the answer have been C? cause y=0 is common in both statements ?

What is the value of $$y$$?

(1) $$y^3+2y=y+2y^2$$. Rearrange and factor out $$y$$ to get $$y(y^2-2y+1)=0$$, which is the same as $$y(y-1)^2=0$$, so $$y=0$$ or $$y=1$$. Not sufficient.

(2) $$y^2=y$$. The same two solutions: $$y=0$$ or $$y=1$$. Not sufficient.

(1)+(2) Nothing new. Not sufficient.

As for your question: if from (2) we had that y=0 or y=2, then the answer would be C: y=0.

Sorry Sir, Will adhere to rule 6 going forward.

Had 2 resulted in y=3 or y=4, answer would have been E ?

No. In this case the question would be flawed: on the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other.

Thus the case when from (1) we have that y=0 or y=1 and from (2) we have that y=3 or y=4, is not possible, since in this case the statements clearly contradict each other.

Hope it's clear.
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Kudos [?]: 135518 [1], given: 12697

Re: M21-16   [#permalink] 10 Feb 2013, 04:04
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M21-16

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