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Joined: 02 Sep 2009
Posts: 42249

Kudos [?]: 132565 [0], given: 12326

Re: m23#17 [#permalink]

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New post 01 Aug 2012, 07:33
voodoochild wrote:
I am a bit confused about this question.

If Ay + B = C and A, B and C are known, then there should be only one value of y = (C-B)/A.

1) C>B This should be sufficient because A, B and C are known. Correct? If C = 5, B = 4, A = 2, I will get a unique value of 'y'.

2) A>1 => Again,...All three variables are known. Hence, Sufficient.

I am really not able to follow the OE about #1 - Consider A= 0 and A=1..Why? A,B and C are known...I am lost.

Can you please help me?


This question is removed from the set. So, I wouldn't worry about it.

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Kudos [?]: 132565 [0], given: 12326

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Joined: 22 Mar 2011
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Kudos [?]: 1072 [1], given: 43

WE: Science (Education)
Quant - Linear equations with parameters [#permalink]

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New post 01 Aug 2012, 09:16
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Relevant to an old question (was M03-Q23):

Consider the the equation \(Ax=B\), where \(A\) and \(B\) are given real numbers, and \(x\) is to be found.
There are three possible scenarios:

1) \(A\neq0\). In this case, the given equation has a unique solution given by \(\frac{B}{A}\). Doesn't matter who is \(B\), it can be also 0, as 0 divided by a non-zero number is 0.
2) \(A = 0\) and \(B = 0\). In this case, the given equation has infinitely many solutions, as for any number \(x\), \(0 * x = 0\).
3) If \(A = 0\), but \(B\neq0\), then the given equation has no solution, because \(Ax = 0 * x = 0 \neq{B}\).

I hope the above can help when discussing any linear equation with one unknown and parameters (letters instead of numbers as coefficients).

PhD in Applied Mathematics
Love GMAT Quant questions and running.

Kudos [?]: 1072 [1], given: 43

Quant - Linear equations with parameters   [#permalink] 01 Aug 2012, 09:16

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