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Re: m23#17 [#permalink]

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New post 01 Aug 2012, 07:33
voodoochild wrote:
I am a bit confused about this question.

If Ay + B = C and A, B and C are known, then there should be only one value of y = (C-B)/A.

1) C>B This should be sufficient because A, B and C are known. Correct? If C = 5, B = 4, A = 2, I will get a unique value of 'y'.

2) A>1 => Again,...All three variables are known. Hence, Sufficient.

I am really not able to follow the OE about #1 - Consider A= 0 and A=1..Why? A,B and C are known...I am lost.

Can you please help me?


This question is removed from the set. So, I wouldn't worry about it.

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Quant - Linear equations with parameters [#permalink]

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New post 01 Aug 2012, 09:16
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Relevant to an old question (was M03-Q23):

Consider the the equation \(Ax=B\), where \(A\) and \(B\) are given real numbers, and \(x\) is to be found.
There are three possible scenarios:

1) \(A\neq0\). In this case, the given equation has a unique solution given by \(\frac{B}{A}\). Doesn't matter who is \(B\), it can be also 0, as 0 divided by a non-zero number is 0.
2) \(A = 0\) and \(B = 0\). In this case, the given equation has infinitely many solutions, as for any number \(x\), \(0 * x = 0\).
3) If \(A = 0\), but \(B\neq0\), then the given equation has no solution, because \(Ax = 0 * x = 0 \neq{B}\).

I hope the above can help when discussing any linear equation with one unknown and parameters (letters instead of numbers as coefficients).

PhD in Applied Mathematics
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Quant - Linear equations with parameters   [#permalink] 01 Aug 2012, 09:16

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