It is currently 16 Dec 2017, 12:53

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# M24 Q 30

Author Message
Senior Manager
Joined: 18 Aug 2009
Posts: 413

Kudos [?]: 145 [0], given: 16

Schools: UT at Austin, Indiana State University, UC at Berkeley
WE 1: 5.5
WE 2: 5.5
WE 3: 6.0

### Show Tags

18 Jan 2010, 18:54
Please explain, how to solve this problem...
Attachments

Untitled.jpg [ 14.02 KiB | Viewed 1504 times ]

_________________

Never give up,,,

Kudos [?]: 145 [0], given: 16

Senior Manager
Joined: 30 Aug 2009
Posts: 281

Kudos [?]: 194 [0], given: 5

Location: India
Concentration: General Management

### Show Tags

19 Jan 2010, 02:43
mirzohidjon wrote:
Please explain, how to solve this problem...

taking different values for x

let x = -2 then we have -2/ |-2| = -1 < -2. NO

let x = -1 then we have -1/ |-1| = -1 < -1. NO

Let x = 0 then we have 0/|0| = 0<0. NO

Let x= 1 then we have 1/|1| = 1< 1. NO

let x = -1/3 then we have (-1/3)/ |(-1/3)| = -1 < (-1/3) YES

let x = 1/2 then we have (1/2)/|(1/2)| = 1 < 1/2 NO

let x = 2 then we have 2/|2| = 1 < 2 YES

so answer b expresses this correctly.

Kudos [?]: 194 [0], given: 5

Intern
Status: Focus
Joined: 02 Jan 2010
Posts: 1

Kudos [?]: [0], given: 1

Schools: Stanford, HAAS, and Kellogs
Re: M24 Q 30 (SHORTER SOLUTION) [#permalink]

### Show Tags

19 Jan 2010, 07:17
x/|x|<x =sgn(x)<x (sgn is signum function)

=>x/|x|<x ={ 1<x; x>=0 OR -1<x ; x<0 }
=> x>1 OR -1<x<0
So, B is right.

Kudos [?]: [0], given: 1

Senior Manager
Joined: 18 Aug 2009
Posts: 413

Kudos [?]: 145 [0], given: 16

Schools: UT at Austin, Indiana State University, UC at Berkeley
WE 1: 5.5
WE 2: 5.5
WE 3: 6.0

### Show Tags

21 Jan 2010, 08:00
Yeah, the problem looks like will require a bit of time...
_________________

Never give up,,,

Kudos [?]: 145 [0], given: 16

Re: M24 Q 30   [#permalink] 21 Jan 2010, 08:00
Display posts from previous: Sort by

# M24 Q 30

Moderator: Bunuel

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.