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M25-22

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BSchool Forum Moderator
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G
Joined: 23 May 2018
Posts: 333
Location: Pakistan
GMAT 1: 770 Q48 V50
GPA: 3.4
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Re: M25-22  [#permalink]

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New post 28 Jun 2018, 01:30
Bunuel wrote:
HinaTabassum wrote:
So, what I understand from this question is that the answer is B because the function described in the question could be stretched to infinity as every number can raised to it's square and there is no given value of x per se. Right, Bunuel ?


The answer is B because for any value of x, f(-2) = f(4) = f(16) = f(16^2) = f(256^2) = .


Thanks Bunuel.
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M25-22  [#permalink]

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New post 12 Jul 2018, 10:05
i knee jerk picked E lol
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Re: M25-22  [#permalink]

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New post 25 Aug 2018, 02:07
i will give a very easy explanation
eq 1. f(x)=f(x2) [f(-2)=f(4)]
thus 2. f(x2)=f(x4) [f(4)=f(16)]
add 1 and 2
f(x2)=f(x4)
f(x2)-f(x4) = 0 thus [f(-2)-f(16)=0]
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Re: M25-22 &nbs [#permalink] 25 Aug 2018, 02:07

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M25-22

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