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M28-30

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Joined: 22 Apr 2017
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Re: M28-30  [#permalink]

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New post 19 Aug 2017, 01:45
kishgau wrote:
From {1,2,3,4,5}, the sets could be formed as 5C1 + 5C2 + 5C3 + 5C4 + 5C5 + 5C0 ( the empty set). I see what you mean. Thank you!


I did the same...left 5C0 out :( Empty set is a subset of any set.
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M28-30  [#permalink]

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New post 30 Oct 2018, 09:20
Such problems can be quickly solved with a set of 2 numbers i.e. {0,1}

Total subsets here will be 4 i.e. 2^2 i.e. {},{0},{1},{0,1} out of which 2 i.e. half of them do not have 0 in them.

Same logic can be applied for 6 numbers, in which 2^6 subsets will be formed and half of them i.e. 32 won't have 0 in them.
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M28-30 &nbs [#permalink] 30 Oct 2018, 09:20

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