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M28-30

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Current Student
Joined: 22 Apr 2017
Posts: 106
Location: India
GMAT 1: 620 Q46 V30
GMAT 2: 620 Q47 V29
GMAT 3: 630 Q49 V26
GMAT 4: 690 Q48 V35
GPA: 3.7

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19 Aug 2017, 02:45
1
kishgau wrote:
From {1,2,3,4,5}, the sets could be formed as 5C1 + 5C2 + 5C3 + 5C4 + 5C5 + 5C0 ( the empty set). I see what you mean. Thank you!

I did the same...left 5C0 out :( Empty set is a subset of any set.
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Joined: 08 Jan 2013
Posts: 103

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30 Oct 2018, 10:20
Such problems can be quickly solved with a set of 2 numbers i.e. {0,1}

Total subsets here will be 4 i.e. 2^2 i.e. {},{0},{1},{0,1} out of which 2 i.e. half of them do not have 0 in them.

Same logic can be applied for 6 numbers, in which 2^6 subsets will be formed and half of them i.e. 32 won't have 0 in them.
M28-30   [#permalink] 30 Oct 2018, 10:20

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