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Re: Machine A and machine B working at their constant respective rates pro [#permalink]
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Bunuel wrote:
Machine A and machine B working at their constant respective rates produced 50 components in 20 minutes. How much time, in minutes, would it have taken machine B working alone at its constant rate to produce 50 components?

(1) Machine A produced 10 fewer components than did machine B.
(2) The rate at which machine B works is 50 percent faster than the rate at which machine A works.


A+B are producing 50 components in 20 minutes.

(1) A produced 10 fewer than B, this means A produced 20 components in 20 minutes while B produced 30 components in 20 minutes. So if B produces 30 in 20 minutes, it produces 1.5 components per minute and thus we can find the time required to produce 50 = 50/1.5 minutes. Sufficient.

(2) So if A produces 'x' components per minute, B produces '1.5x' components per minute. So in 1 minute, A+B produce = x+1.5x = 2.5x components. Thus in 20 minutes they produce = 20*2.5x = 50x components.. but this is given as 50 only. So x=1. Thus A produces 1 per minute while B produces 1.5 per minute. This data now becomes same as in first statement. So Sufficient.

Hence D answer
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Re: Machine A and machine B working at their constant respective rates pro [#permalink]
Ans: D

We are given that Machine A and machine B together produced 50 components in 20 minutes. and we need to find time taken by B for 50 components.

Stat (1): Machine A produced 10 fewer components than did machine B.
lets say MA produces x comp/min so MB produces x+10 Comp/min. Together they will produce 2x+10 comp/min, which is equal to 50/20 (given). here we can get the value of x which will give us the speed of MB. (Suff)

Stat (2): The rate at which machine B works is 50 percent faster than the rate at which machine A works. Again relation between MA and MB speed is given so we can find the individual speed and thus (Suff)

Final Ans: D (Both stat alone are sufficient to ans the question)
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Re: Machine A and machine B working at their constant respective rates pro [#permalink]
Bunuel wrote:
Machine A and machine B working at their constant respective rates produced 50 components in 20 minutes. How much time, in minutes, would it have taken machine B working alone at its constant rate to produce 50 components?

(1) Machine A produced 10 fewer components than did machine B.
(2) The rate at which machine B works is 50 percent faster than the rate at which machine A works.


Given : Combined rate = 50 components / 20 minutes

A + B = 50 ----- (I)

Question : Time taken by B to produce 50 components ?

St 1: A = B - 10 -----(II)

From I and II we get

B + B - 10 = 50

2B = 60

B = 30 components / 20 minutes

We can find out time for producing 50 components (Sufficient)

St 2: R(B) = 1.5R(A) -----(III)

From I and III we an again find out production capacity of B. (Sufficient)

(D)
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Re: Machine A and machine B working at their constant respective rates pro [#permalink]
(1) Machine A produced 10 fewer components than did machine B.

It's not clear, we don't know the period of time in which Machine A produced 10 fewer than Machine B. Event we got some information in the question, on my opinion its not really obvious to conclude the split.

I'm maybe wrong on this point, if someone have an explanation, I'll be happy to read it. Thanks.
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Re: Machine A and machine B working at their constant respective rates pro [#permalink]
Bunuel wrote:
(1) Machine A produced 10 fewer components than did machine B.
.


Isn't the coloured part a little ambiguous as in what time A produced 10 fewer components is not mentioned in the question.
Thanks in advance.
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Re: Machine A and machine B working at their constant respective rates pro [#permalink]
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Re: Machine A and machine B working at their constant respective rates pro [#permalink]
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