Since Machine A does a job in 24 hours,
lets assume the number of units of work done to be a multiple of 24(for eg, 72 units)
So the rate of Machine A doing the work is
3 units/hourIt has been given that B does the work at \(\frac{2}{3}\)rd the rate of A.
Therefore Machine B does the work at the rate of
2 units/hourSince Machine A does the work for 8 hours,
Machine B does the rest of the work for
x days till the work is complete.
8*3 +
x*2 = 72(total units of work)
2
x = 48
x = 24
Therefore, Machine B takes 24 hours to complete the remaining work(Option C)
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