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Re: Machine A working alone can complete a job in 3 1/2 hours. Machine B [#permalink]
Lolaergasheva wrote:
Machine A working alone can complete a job in hours. Machine B working alone can do the same job in hours. How long will it take both machines working together at their respective constant rates to complete the job?

(A) 1 hr 10 min
(B) 2 hr
(C) 4 hr 5 min
(D) 7 hr
(E) 8 hr 10 min

I got answer E but it is incorrect


I think the question is incomplete in its present form. The details of number of hours for both machines is not there. If they were given (say x and y), then you could get the total number of hours by simple formula of 1/x+1/y = 1/combined rate
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Re: Machine A working alone can complete a job in 3 1/2 hours. Machine B [#permalink]
Machine A working alone can complete a job in 3 1/2 hours. Machine B working alone can do the same job in 4 2/3 hours. How long will it take both machines working together at their respective constant rates to complete the job?

--just remember rate*time=job
Lets consider they both need to work for t hours to get the job done..

So, rate*time=job (Here job is 1 as it needs to be completed)
rate for type A machine =1/210 -- converting hrs to minutes
similarly rate for type A machine =1/280

Finally we have,
(1/210)*t + (1/280)*t=1
t=280*210/490
t=120 mins=2 hrs

Answer B should be correct.
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Re: Machine A working alone can complete a job in 3 1/2 hours. Machine B [#permalink]
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The question is quit simple, we need not convert them to minutes.

Machine A : 3 1/2 hrs = 7/2 hrs. So, in one hour the work would be 2/7.

Machine A : 4 2/3 hrs = 14/3 hrs. So, in one hour the work would be 3/14.

Combined rate of both machines,

2/7 + 3/14 = 7/14 = 1/2.

So, the complete work is done in 2 hours.
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Re: Machine A working alone can complete a job in 3 1/2 hours. Machine B [#permalink]
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We can also use LCM method to solve this Time & Work related question.

Since it's given that Machine A working alone can complete a job in 3 1/2 hours= 7/2 hrs. Machine B working alone can do the same job in 4 2/3 hours = 14/3 hours.

We assume total Work as LCM ( 7,14 ) = 14 units

Per hour Work of A = 14/(7/2) = 4 units/hr

Per hour Work of B = 14/(14/3) = 3 units/hr

Machine A+ B will do 4 + 3 = 7 units/hr

Time taken by both the machines to complete the task = Total Work/Per hour work of A and B = 14/7 = 2 hrs.

Option B is the answer.

Thanks,
Clifin J Francis
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Re: Machine A working alone can complete a job in 3 1/2 hours. Machine B [#permalink]
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Re: Machine A working alone can complete a job in 3 1/2 hours. Machine B [#permalink]
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