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Marcia took a trip consisting of three segments at three

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Marcia took a trip consisting of three segments at three [#permalink]

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New post 17 Jul 2013, 09:50
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72% (01:15) correct 28% (01:12) wrong based on 171 sessions

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Marcia took a trip consisting of three segments at three different speeds: she drove a distance of (5D) at a speed of (2v), then a distance of (4D) at a speed of (3v), then a distance of D at a speed of (6v). In terms of D & v, what was the total time of Marcia’s trip?
(A) \(\frac{4D}{v}\)

(B) \(\frac{4v}{D}\)

(C) \(\frac{10D}{11v}\)

(D) \(\frac{10v}{11D}\)

(E) \(\frac{11D}{10v}\)

For help with plugging in numbers as a strategy, as well as a complete explanation of this problem, see:
http://magoosh.com/gmat/2013/how-to-plu ... questions/

Mike :-)
[Reveal] Spoiler: OA

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Last edited by mikemcgarry on 17 Jul 2013, 10:47, edited 1 time in total.

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Re: Marcia took a trip consisting of three segments at three [#permalink]

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mikemcgarry wrote:
Marcia took a trip consisting of three segments at three different speeds: she drove a distance of (5D) at a speed of (2v), then a distance of (4D) at a speed of (3v), then a distance of D at a speed of (6v). In terms of D & v, what was the total time of Marcia’s trip?
(A) \(\frac{2D}{v}\)

(B) \(\frac{2v}{D}\)

(C) \(\frac{10D}{11v}\)

(D) \(\frac{10v}{11D}\)

(E) \(\frac{11D}{10v}\)

For help with plugging in numbers as a strategy, as well as a complete explanation of this problem, see:
http://magoosh.com/gmat/2013/how-to-plu ... questions/

Mike :-)


\(speedXtime=space\) so \(time=\frac{space}{speed}\)

\(time=time_1+time_2+time_3=\frac{5D}{2v}+\frac{4D}{3v}+\frac{D}{6v}=\frac{4D}{v}\)

Am I right? Is there a typo Mike?
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Re: Marcia took a trip consisting of three segments at three [#permalink]

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New post 17 Jul 2013, 10:49
Zarrolou wrote:

\(speedXtime=space\) so \(time=\frac{space}{speed}\)

\(time=time_1+time_2+time_3=\frac{5D}{2v}+\frac{4D}{3v}+\frac{D}{6v}=\frac{4D}{v}\)

Am I right? Is there a typo Mike?

Odds Bodkins! I'm sorry! Indeed, that is a typo! Sir, you are of course quite correct. Thank you very much for pointing this out! I changed it here, and now I have to change it on the blog.
Thanks again,
Mike :-)
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Re: Marcia took a trip consisting of three segments at three [#permalink]

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New post 17 Jul 2013, 11:01
d=rt....therefore t = d/r

1st trip t = 5d/2v
2nd trip t = 4d/3v
3rd trip t = d/6v

Add all the t's up and you get 24D/6v = 4D/v. Answer (A)

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Re: Marcia took a trip consisting of three segments at three [#permalink]

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New post 03 Aug 2013, 12:21
Total time = total distance/total rate:

We have three different distances and three different rates:

5d/2v
4d/3v
1d/6v

5d/2v + 4d/3v + 1d/6v
15d/6v + 8d/6v + 1d/6v
24d/6v
4d/v

Answer: (C) \frac{10D}{11v}

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Re: Marcia took a trip consisting of three segments at three [#permalink]

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Re: Marcia took a trip consisting of three segments at three [#permalink]

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New post 17 Feb 2017, 08:42
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Marcia took a trip consisting of three segments at three   [#permalink] 17 Feb 2017, 08:42
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