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# Maribel must divide 60 candies among herself and her 12 cousins, altho

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Math Expert
Joined: 02 Sep 2009
Posts: 53066
Maribel must divide 60 candies among herself and her 12 cousins, altho  [#permalink]

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31 Jan 2019, 23:24
00:00

Difficulty:

35% (medium)

Question Stats:

67% (01:31) correct 33% (01:13) wrong based on 9 sessions

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Maribel must divide 60 candies among herself and her 12 cousins, although there is no requirement that the candies be divided equally. If Maribel is to have more candies than everyone else, what is the least number of candies she could have?

A. 5
B. 6
C. 7
D. 8
E. 9

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Re: Maribel must divide 60 candies among herself and her 12 cousins, altho  [#permalink]

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31 Jan 2019, 23:35
Proceeding by options is the best procedure here. As we have to find the least possible candies Maribel can have we can start from option A.

A) 5

If Maribel has 5 candies the remaining 55 candies have to be divided among 12 people. If we divide them equally then everyone will get 4 candies at first and then remaining 7 candies can be divided giving 1 candy to 7 people. Now Maribel has 5 candies and few others also have 5 candies. This cannot be the case as Maribel should have more candies than all other. So 5 cannot be the possible value.

B) 6

If Maribel has 6 candies then remaining 54 candies can be divided among others equally first. Remaining 6 candies can be given to 6 people, each with 1. Now Maribel has 6 candies and 6 other people have 5 candies and others have 4 candies. This condition is perfectly fine. So 6 is minimum candies that Maribel can have.

OPTION: B
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Chaitanya

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Re: Maribel must divide 60 candies among herself and her 12 cousins, altho   [#permalink] 31 Jan 2019, 23:35
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