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Well I suppose if you were to find all values that would fit the equation: 23x+21y=130

If you subtract 130-23 =107, check if this is divisible by 21, it is NOT DIVISIBLE Next try 130-2(23) = 130-46 =84, check if divisible by 21, it is since 21*4 = 84

Therefore we can conclude that x=2 and y=4 satisfy the above equation and B is sufficient

2) 23x+21y=130 x,y are both positive integers. y is equal to or less than 6 (~130/21). If you try all possible values of y, you will find merely y=4, x=2 as the correct answer. So we do not need x+y as 1 shows to find the final answer.