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# Marty's Pizza Shop guarantees that their pizzas all have a

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Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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27 Feb 2013, 04:14
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Marty's Pizza Shop guarantees that their pizzas all have at least 75% of the surface area covered with toppings, with a crust of uniform width surrounding them. If you order their best seller – a circular pizza with a diameter of 16 inches – what is the maximum width you can expect to see for the crust?

A. 0.8 inches
B. 1.1 inches
C. 1.6 inches
D. 2.0 inches
E. 2.5 inches
[Reveal] Spoiler: OA

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Last edited by Bunuel on 27 Feb 2013, 05:19, edited 1 time in total.
Edited the question.

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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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27 Feb 2013, 06:17
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emmak wrote:
Marty's Pizza Shop guarantees that their pizzas all have at least 75% of the surface area covered with toppings, with a crust of uniform width surrounding them. If you order their best seller – a circular pizza with a diameter of 16 inches – what is the maximum width you can expect to see for the crust?

A. 0.8 inches
B. 1.1 inches
C. 1.6 inches
D. 2.0 inches
E. 2.5 inches

The area of 16 inches pizza is $$\pi{R^2}=8^2\pi=64\pi$$.

The minimum area covered with toppings is $$\frac{3}{4}*64\pi=48\pi$$ --> the radius of the toppings is $$\pi{r^2}=48\pi$$ --> $$r=4\sqrt{3}\approx{6.9}$$.

The maximum width for the crust possible = R - r = 8 - 6.9 = 1.1 inches.

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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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03 Mar 2013, 06:50
Hmmm not an official question and the wording is tough on this
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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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03 Mar 2013, 21:07
emmak wrote:
Marty's Pizza Shop guarantees that their pizzas all have at least 75% of the surface area covered with toppings, with a crust of uniform width surrounding them. If you order their best seller – a circular pizza with a diameter of 16 inches – what is the maximum width you can expect to see for the crust?

A. 0.8 inches
B. 1.1 inches
C. 1.6 inches
D. 2.0 inches
E. 2.5 inches

Total Area = 8 * 8 * pi

Surface = .75 * 64 * pi = 48 pi
Radius of surface = 4 sqrt (3) ~ 6.8

Radius width = 8 - 6.8 = 1.2

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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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23 Sep 2014, 05:38
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Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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23 Sep 2014, 06:20
Bunuel wrote:
emmak wrote:
Marty's Pizza Shop guarantees that their pizzas all have at least 75% of the surface area covered with toppings, with a crust of uniform width surrounding them. If you order their best seller – a circular pizza with a diameter of 16 inches – what is the maximum width you can expect to see for the crust?

A. 0.8 inches
B. 1.1 inches
C. 1.6 inches
D. 2.0 inches
E. 2.5 inches

The area of 16 inches pizza is $$\pi{R^2}=8^2\pi=64\pi$$.

The minimum area covered with toppings is $$\frac{3}{4}*64\pi=48\pi$$ --> the radius of the toppings is $$\pi{r^2}=48\pi$$ --> $$r=4\sqrt{3}\approx$$ 6,9

The maximum width for the crust possible = R - r = 8 - 6.9 = 1.1 inches.

$$r=4\sqrt{3}=6.9282....$$.

The maximum width for the crust possible = R - r = 8 - 6.9282... = 1.0717.... inches. -----> 1,1 width would make the surface area covered with topping less than 75%

I know this might be picky, but shouldn't OA be A ?
Does GMAT give these possible answers where rounding errors become very important
Please fill me in case Im missing something (which I probably do)
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Last edited by TehMoUsE on 23 Sep 2014, 06:26, edited 1 time in total.

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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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23 Sep 2014, 06:25
TehMoUsE wrote:
Bunuel wrote:
emmak wrote:
Marty's Pizza Shop guarantees that their pizzas all have at least 75% of the surface area covered with toppings, with a crust of uniform width surrounding them. If you order their best seller – a circular pizza with a diameter of 16 inches – what is the maximum width you can expect to see for the crust?

A. 0.8 inches
B. 1.1 inches
C. 1.6 inches
D. 2.0 inches
E. 2.5 inches

The area of 16 inches pizza is $$\pi{R^2}=8^2\pi=64\pi$$.

The minimum area covered with toppings is $$\frac{3}{4}*64\pi=48\pi$$ --> the radius of the toppings is $$\pi{r^2}=48\pi$$ --> $$r=4\sqrt{3}\approx{6.9}$$.

The maximum width for the crust possible = R - r = 8 - 6.9 = 1.1 inches.

$$r=4\sqrt{3}\={6.9282....}$$.

The maximum width for the crust possible = R - r = 8 - 6.9282... = 1.0717.... inches. -----> 1,1 width would make the surface area covered with topping less than 75%

I know this might be picky, but shouldn't OA be A ?

The approximate maximum is 1.1 inches.
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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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23 Sep 2014, 06:32
Bunuel wrote:
The approximate maximum is 1.1 inches.

I understand that, but the question doesn't say anything about approximations.

Is it silently implied in GMAT that you round up to the closest number, even tho it would give you the "wrong" answer?
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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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23 Sep 2014, 06:37
TehMoUsE wrote:
Bunuel wrote:
The approximate maximum is 1.1 inches.

I understand that, but the question doesn't say anything about approximations.

Is it silently implied in GMAT that you round up to the closest number, even tho it would give you the "wrong" answer?

Word "approximate" is missing there. It should be "what is the approximate maximum width you can expect to see for the crust?"
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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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23 Sep 2014, 07:31
Hi Bunuel,

I am not able to find the solution with this method.

x be the width of the surrounding

pi (8-x)^2/pi(8)^2 = 3/4

does not lead to the answer..I am not able to find whats wrong in this approach.

Regards,
Ravi

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24 Sep 2014, 05:29
email2vm wrote:
Hi Bunuel,

I am not able to find the solution with this method.

x be the width of the surrounding

pi (8-x)^2/pi(8)^2 = 3/4

does not lead to the answer..I am not able to find whats wrong in this approach.

Regards,
Ravi

There is nothing wrong with this approach.

$$\frac{\pi (8-x)^2}{\pi(8)^2} = \frac{3}{4}$$ --> $$(8-x)^2=48$$ --> $$8-x=4\sqrt{3}=6.9$$ --> $$x=8-6.9=1.1$$.
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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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31 May 2015, 11:01
Bunuel wrote:
TehMoUsE wrote:
Bunuel wrote:
The approximate maximum is 1.1 inches.

I understand that, but the question doesn't say anything about approximations.

Is it silently implied in GMAT that you round up to the closest number, even tho it would give you the "wrong" answer?

Word "approximate" is missing there. It should be "what is the approximate maximum width you can expect to see for the crust?"

I think the keyword here is "at least" so, if 75% calculation comes to 1.08 we have no choice but to round up and select the closest, which in this case is 1.10 and not 1.06, which will breach the requirement of "at least 75%".. Lemme know your views. Thanks.

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Re: Marty's Pizza Shop guarantees that their pizzas all have a [#permalink]

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13 Dec 2016, 20:32
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Marty's Pizza Shop guarantees that their pizzas all have a   [#permalink] 13 Dec 2016, 20:32
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