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Mary goes from her house to the library at a constant speed rate of 40

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Mary goes from her house to the library at a constant speed rate of 40  [#permalink]

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New post Updated on: 23 Feb 2019, 00:15
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Mary goes from her house to the library at a constant speed rate of 40 miles per hour and come back from the library to her house at a constant rate of 45 miles per hour along the same route. What is the distance of the route?

(1) The difference between the round trip’s times taken is 2 minutes
(2) The total amount of minutes for the round trip taken is 34 minutes

Originally posted by indu1954 on 22 Feb 2019, 13:51.
Last edited by Bunuel on 23 Feb 2019, 00:15, edited 2 times in total.
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Re: Mary goes from her house to the library at a constant speed rate of 40  [#permalink]

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New post 23 Feb 2019, 00:37
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OA:D

Let the distance between Mary's Home and Library be \(x\).
\(Average Speed_{(Home ->Library)} = 40\) miles per hour
\(Average Speed_{(Library ->Home)} = 45\) miles per hour

(1) The difference between the round trip’s times taken is 2 minutes

i.e \(\frac{x}{Average Speed_{(Home ->Library)}} - \frac{x}{Average Speed_{(Library ->Home)}}=2\)

\(\frac{x}{40} - \frac{x}{45}=2\)

We can easily find out the value of x, So Statement 1 alone is sufficient.

(2) The total amount of minutes for the round trip taken is 34 minutes

i.e \(\frac{x}{Average Speed_{(Home ->Library)}} + \frac{x}{Average Speed_{(Library ->Home)}}=34\)

\(\frac{x}{40} + \frac{x}{45}=34\)

We can easily find out the value of \(x\), So Statement 2 alone is sufficient.
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Re: Mary goes from her house to the library at a constant speed rate of 40   [#permalink] 23 Feb 2019, 00:37
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Mary goes from her house to the library at a constant speed rate of 40

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