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# Mary goes from her house to the library at a constant speed rate of 40

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Intern
Joined: 02 Nov 2017
Posts: 28
Location: India
GPA: 3.87
Mary goes from her house to the library at a constant speed rate of 40  [#permalink]

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Updated on: 23 Feb 2019, 00:15
2
00:00

Difficulty:

45% (medium)

Question Stats:

56% (01:24) correct 44% (01:55) wrong based on 68 sessions

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Mary goes from her house to the library at a constant speed rate of 40 miles per hour and come back from the library to her house at a constant rate of 45 miles per hour along the same route. What is the distance of the route?

(1) The difference between the round trip’s times taken is 2 minutes
(2) The total amount of minutes for the round trip taken is 34 minutes

Originally posted by indu1954 on 22 Feb 2019, 13:51.
Last edited by Bunuel on 23 Feb 2019, 00:15, edited 2 times in total.
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Joined: 18 Jun 2018
Posts: 257
Re: Mary goes from her house to the library at a constant speed rate of 40  [#permalink]

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23 Feb 2019, 00:37
2
OA:D

Let the distance between Mary's Home and Library be $$x$$.
$$Average Speed_{(Home ->Library)} = 40$$ miles per hour
$$Average Speed_{(Library ->Home)} = 45$$ miles per hour

(1) The difference between the round trip’s times taken is 2 minutes

i.e $$\frac{x}{Average Speed_{(Home ->Library)}} - \frac{x}{Average Speed_{(Library ->Home)}}=2$$

$$\frac{x}{40} - \frac{x}{45}=2$$

We can easily find out the value of x, So Statement 1 alone is sufficient.

(2) The total amount of minutes for the round trip taken is 34 minutes

i.e $$\frac{x}{Average Speed_{(Home ->Library)}} + \frac{x}{Average Speed_{(Library ->Home)}}=34$$

$$\frac{x}{40} + \frac{x}{45}=34$$

We can easily find out the value of $$x$$, So Statement 2 alone is sufficient.
Re: Mary goes from her house to the library at a constant speed rate of 40   [#permalink] 23 Feb 2019, 00:37
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