Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 24 May 2017, 22:58

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# math problem

Author Message
Intern
Joined: 07 Sep 2008
Posts: 25
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

13 Sep 2008, 02:50
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

(x^2 + 6x +9) + 6(x+3) + 9 = 0, then x= ??

Many thanks,
Andreas
Intern
Joined: 11 Sep 2008
Posts: 16
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

13 Sep 2008, 08:01
factoring gives you (x+6)(x+6)=0 [check: x^2+6x+6x+36 = x^2+12x+36].
so (x+6)(x+6), mean the ansewr is -6 or -6....i.e. -6.
substitute in the original form to get check (you will get 0=0)
Intern
Joined: 07 Sep 2008
Posts: 25
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

13 Sep 2008, 15:02
thats great ! Thank you !
Manager
Joined: 28 Aug 2008
Posts: 101
Followers: 1

Kudos [?]: 33 [0], given: 0

### Show Tags

13 Sep 2008, 19:35
Yeah... just multiply out 6(x+3) and sum:

x^2 + 6x + 9 + 6x + 18 + 9 = 0

x^2 + 12x + 36 = 0

( x+6)(x+6) = 0

Intern
Joined: 03 Sep 2008
Posts: 22
Followers: 0

Kudos [?]: 10 [0], given: 0

### Show Tags

14 Sep 2008, 10:29
Here's a slightly different approach.

You recognize that original equation has the form a^2+2ab+b^2=(a+b)^2
with a=(x+3) and b = 3.

Therefore the original equation can be written as

(x+3+3)^2=0 ===> x = - 6
Re: math problem   [#permalink] 14 Sep 2008, 10:29
Display posts from previous: Sort by