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# math problem

Author Message
Intern
Joined: 08 Jun 2010
Posts: 17
Followers: 0

Kudos [?]: 1 [0], given: 1

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22 Jul 2010, 15:39
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (00:00) wrong based on 4 sessions

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I got this problem if 5^2 and 3^3 are factors of n*2^5*6^2*7^3 what is the least possible value of n

the answer choices were 25 27 45 75 125
CEO
Status: Nothing comes easy: neither do I want.
Joined: 12 Oct 2009
Posts: 2786
Location: Malaysia
Concentration: Technology, Entrepreneurship
Schools: ISB '15 (M)
GMAT 1: 670 Q49 V31
GMAT 2: 710 Q50 V35
Followers: 238

Kudos [?]: 1726 [1] , given: 235

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22 Jul 2010, 15:46
1
KUDOS
Jazzy12 wrote:
I got this problem if 5^2 and 3^3 are factors of n*2^5*6^2*7^3 what is the least possible value of n

the answer choices were 25 27 45 75 125

Ans is D 75

as per given question $$\frac{n* 2^5 * 6^2 * 7^3}{(5^2 * 3^3)}$$ should have integral value

for this to be true n= 5^2 * 3 = 75

as 6^2 will cancel 3^2 from the denominator.
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Re: math problem   [#permalink] 22 Jul 2010, 15:46
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