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# Mike, Jim and Bob are all professional fisherman. Mike can catch 21

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Math Expert
Joined: 02 Sep 2009
Posts: 60631
Mike, Jim and Bob are all professional fisherman. Mike can catch 21  [#permalink]

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27 Jun 2016, 04:09
00:00

Difficulty:

35% (medium)

Question Stats:

77% (02:19) correct 23% (02:54) wrong based on 145 sessions

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Mike, Jim and Bob are all professional fisherman. Mike can catch 21 fish in one hour, Jim can catch twice as much and Bob can catch 50% more than Jim. If the three started to fish together and after 40 minutes Mike and Bob left, how many fish did the three fishermen catch in one hour?

A. 64.
B. 72.
C. 86.
D. 98.
E. 112.

_________________
Intern
Joined: 23 Sep 2014
Posts: 33
Location: India
Concentration: Marketing, Finance
GMAT 1: 670 Q48 V34
Re: Mike, Jim and Bob are all professional fisherman. Mike can catch 21  [#permalink]

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27 Jun 2016, 05:48
We are given
Rate of catching the fish for all three people
M - 21 fish/hour
J - 42 fish/hour
B - 63 fish/hour.

So in 1 hour, if they work together they can catch - 126 fish.

It is given they work together for first 40 min,

So by then they will have caught 2/3 * 128 = 84

Last 20 mins J will work alone and he can catch 1/3*42 = 14 in the remaining 20 mins, thus the total fishes they will catch in one hour = 84+14 = 98

(D)
Director
Joined: 20 Feb 2015
Posts: 731
Concentration: Strategy, General Management
Re: Mike, Jim and Bob are all professional fisherman. Mike can catch 21  [#permalink]

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27 Jun 2016, 05:55
mike and bob worked together for 2/3 hours
mike caught 21*2/3=14 fish
bob caught 63*2/3=42 fish
mike and bob left at this point

total fish caught in an hour,

14+42+what Jim caught in an hour
Jim can catch 2*21 =42 fish in an hour

14+42+42=98
Math Expert
Joined: 02 Aug 2009
Posts: 8336
Re: Mike, Jim and Bob are all professional fisherman. Mike can catch 21  [#permalink]

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27 Jun 2016, 06:55
Bunuel wrote:
Mike, Jim and Bob are all professional fisherman. Mike can catch 21 fish in one hour, Jim can catch twice as much and Bob can catch 50% more than Jim. If the three started to fish together and after 40 minutes Mike and Bob left, how many fish did the three fishermen catch in one hour?

A. 64.
B. 72.
C. 86.
D. 98.
E. 112.

Hi,
JUST another way...
All of them catch fishes in relation to number 21....
and there is nothing in time that should cancel out 7, so our ANS should be a multiple of 7...

ONLY D and E are multiples of 7..

Now the addition of all three 21, double that and 50% above that should be a ODD number as 21 is added to two EVEN quantities that are multiple of 42...
40 Minutes means 2/3 hour... so our answer should be a multiple of 2 and not 4..
ONLY D is left
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Joined: 05 May 2016
Posts: 35
Re: Mike, Jim and Bob are all professional fisherman. Mike can catch 21  [#permalink]

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20 Jul 2016, 08:43
believer700 wrote:
We are given
Rate of catching the fish for all three people
M - 21 fish/hour
J - 42 fish/hour
B - 63 fish/hour.

So in 1 hour, if they work together they can catch - 126 fish.

It is given they work together for first 40 min,

So by then they will have caught 2/3 * 128 = 84

Last 20 mins J will work alone and he can catch 1/3*42 = 14 in the remaining 20 mins, thus the total fishes they will catch in one hour = 84+14 = 98

(D)

Quote:
Chetan Sir:
When in the question it is mentioned that :
"Mike, Jim and Bob are all professional fisherman. Mike can catch 21 fish in one hour, Jim can catch twice as much and Bob can catch 50% more than Jim."

How did you arrive at the following rate of catching:
M - 21 fish/hour
J - 42 fish/hour
B - 63 fish/hour.

Please provide a detailed explanation.
Thanks in advance.

Regards,
Yosita
Re: Mike, Jim and Bob are all professional fisherman. Mike can catch 21   [#permalink] 20 Jul 2016, 08:43
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# Mike, Jim and Bob are all professional fisherman. Mike can catch 21

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