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# Mike, Steve, and Daryl take turns driving on a road trip. Mike drives

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Math Expert
Joined: 02 Sep 2009
Posts: 54544
Mike, Steve, and Daryl take turns driving on a road trip. Mike drives  [#permalink]

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28 Jul 2017, 08:54
00:00

Difficulty:

15% (low)

Question Stats:

83% (01:52) correct 17% (01:47) wrong based on 70 sessions

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Mike, Steve, and Daryl take turns driving on a road trip. Mike drives at an average of 60 mph, Steve drives at an average of 5o mph, and Daryl, the daredevil, drives at 80 mph. If Mike drives for 4 hours, Steve drives for 3 hours, and Daryl drives for 90 minutes, approximately what percent of the total miles does Daryl drive?

A. 15%
B. 18%
C. 20%
D. 24%
E. 32%

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Mike, Steve, and Daryl take turns driving on a road trip. Mike drives  [#permalink]

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28 Jul 2017, 09:10
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Bunuel wrote:
Mike, Steve, and Daryl take turns driving on a road trip. Mike drives at an average of 60 mph, Steve drives at an average of 5o mph, and Daryl, the daredevil, drives at 80 mph. If Mike drives for 4 hours, Steve drives for 3 hours, and Daryl drives for 90 minutes, approximately what percent of the total miles does Daryl drive?

A. 15%
B. 18%
C. 20%
D. 24%
E. 32%

This problem is straightforward $$rt=D$$, then Daryl/total * 100 as percent of total miles driven

Mike drives at average of 60 mph for 4 hours = 240 miles

Steve drives at average of 50 mph for 3 hours = 150 miles

Daryl drives at average of 80 mph for $$\frac{3}{2}$$ hours = 120 miles

Total distance is 240 + 150 + 120 = 510 miles

What percent of total miles does Daryl drive?

$$\frac{120 mi}{510 mi}$$ * 100 = approx 24%

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Mike, Steve, and Daryl take turns driving on a road trip. Mike drives   [#permalink] 28 Jul 2017, 09:10
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