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# miles driven...gmat prep

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Intern
Joined: 25 Jul 2006
Posts: 44

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10 Dec 2006, 01:19
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

need some help on this one...

Cheers!
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Kudos [?]: 11 [0], given: 0

Intern
Joined: 17 Nov 2006
Posts: 19

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10 Dec 2006, 01:35
Ritesh wrote:
need some help on this one...

Cheers!

t1 = 5/30 + (x-5)/60

t2= x/60

(t1-t2)/t2

(10 + x - 5 -x )/x

5/x

hence E

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Senior Manager
Joined: 05 Oct 2006
Posts: 266

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10 Dec 2006, 01:53
travel time before = 5/30
travel time after = 5/60

hence %age increase = (5/30 - 5/60)/5/30 *100 = 50 %

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Intern
Joined: 25 Jul 2006
Posts: 44

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10 Dec 2006, 11:29
yeh now i know wht a fool i have been...thks ppl

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Senior Manager
Joined: 20 Feb 2006
Posts: 373

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10 Dec 2006, 12:36
Original travel time = 5/30 + x-5/60 = 5+x/60

If travelled whole distance at 60 time = x/60

Difference in time = (5+x/60) - (x/60) = 5/60

Difference/time if travelled at 60 = (5/60)/ (x/60) = 300/60x = 5/x

Convert to %: 100*5/x = 500/x

E

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10 Dec 2006, 12:36
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