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Mixtures

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Senior Manager
Joined: 25 Jun 2009
Posts: 289

Kudos [?]: 216 [0], given: 4

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10 Dec 2009, 21:26
Some part of a 50% solution of acid was replaced with an equal amount of 30% solution of acid. If, as a result, 40% solution of acid was obtained, what part of the original solution was replaced?

* 1/5
* 1/4
* 1/2
* 3/4
* 4/5

Can someone help me with this? I am not understanding their solution very well.

Kudos [?]: 216 [0], given: 4

CIO
Joined: 02 Oct 2007
Posts: 1218

Kudos [?]: 979 [0], given: 334

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11 Dec 2009, 01:11
Hi,
This question has already been discussed here:
m25-75372.html

If you can't find the discussion you need in the thread above, please use Forum Search or Custom Google Search available at the top of every page.

Please do not create duplicate topics. Thank you for cooperation .
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Kudos [?]: 979 [0], given: 334

Re: Mixtures   [#permalink] 11 Dec 2009, 01:11
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Mixtures

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