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03 Jan 2016, 13:48
00:00

Difficulty:

55% (hard)

Question Stats:

65% (01:56) correct 35% (01:38) wrong based on 79 sessions

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Mr. Jones spends $76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase? (1) Adult movie tickets cost$ 11 each and children’s movie tickets cost $7 each. (2) Mr. Jones bought two more adult tickets than children’s tickets. _________________ Senior Manager Joined: 10 Mar 2013 Posts: 495 Location: Germany Concentration: Finance, Entrepreneurship GMAT 1: 580 Q46 V24 GPA: 3.88 WE: Information Technology (Consulting) Re: Mr. Jones spends$ 76 on movie tickets for a group of adults and child  [#permalink]

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03 Jan 2016, 16:31
Bunuel wrote:
Mr. Jones spends $76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase? (1) Adult movie tickets cost$ 11 each and children’s movie tickets cost $7 each. (2) Mr. Jones bought two more adult tickets than children’s tickets. (1) 11a + 7c=76 --> $$c=\frac{76-11a}{7}$$, so we have here a unique combination a=5, c=3 Sufficient (2) Clearly not sufficient, as we don't know the total amount Answer A _________________ When you’re up, your friends know who you are. When you’re down, you know who your friends are. Share some Kudos, if my posts help you. Thank you ! 800Score ONLY QUANT CAT1 51, CAT2 50, CAT3 50 GMAT PREP 670 MGMAT CAT 630 KAPLAN CAT 660 Senior Manager Joined: 11 Nov 2014 Posts: 326 Location: India Concentration: Finance, International Business WE: Project Management (Telecommunications) Re: Mr. Jones spends$ 76 on movie tickets for a group of adults and child  [#permalink]

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07 Jan 2016, 06:36
BrainLab wrote:
Bunuel wrote:
Mr. Jones spends $76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase? (1) Adult movie tickets cost$ 11 each and children’s movie tickets cost $7 each. (2) Mr. Jones bought two more adult tickets than children’s tickets. (1) 11a + 7c=76 --> $$c=\frac{76-11a}{7}$$, so we have here a unique combination a=5, c=3 Sufficient (2) Clearly not sufficient, as we don't know the total amount Answer A We know the total 76$ so D
5 & 3 resp
Math Expert
Joined: 02 Aug 2009
Posts: 7563
Re: Mr. Jones spends $76 on movie tickets for a group of adults and child [#permalink] ### Show Tags 07 Jan 2016, 07:19 paidlukkha wrote: BrainLab wrote: Bunuel wrote: Mr. Jones spends$ 76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase?

(1) Adult movie tickets cost $11 each and children’s movie tickets cost$ 7 each.
(2) Mr. Jones bought two more adult tickets than children’s tickets.

(1) 11a + 7c=76 --> $$c=\frac{76-11a}{7}$$, so we have here a unique combination a=5, c=3 Sufficient
(2) Clearly not sufficient, as we don't know the total amount

We know the total 76$so D 5 & 3 resp Hi, you may know the total amount and the info that there are 2 more adult tickets than children's tickets.. but till we know some relation or values of individual tickets, we cannot say anything about the final number.. you are unconsciously carrying forward the info of statement 1 to statement 2.. so 2 is not sufficient.. A _________________ Senior Manager Joined: 11 Nov 2014 Posts: 326 Location: India Concentration: Finance, International Business WE: Project Management (Telecommunications) Re: Mr. Jones spends$ 76 on movie tickets for a group of adults and child  [#permalink]

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07 Jan 2016, 09:45
Hi,
you may know the total amount and the info that there are 2 more adult tickets than children's tickets..
but till we know some relation or values of individual tickets, we cannot say anything about the final number..
you are unconsciously carrying forward the info of statement 1 to statement 2..
so 2 is not sufficient..
A[/quote]

No
1$each 37 adults 39 children 76$
Intern
Joined: 02 Jul 2015
Posts: 35
WE: Investment Banking (Investment Banking)

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22 Mar 2019, 01:44
Bunuel wrote:
Mr. Jones spends $76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase? (1) Adult movie tickets cost$ 11 each and children’s movie tickets cost $7 each. (2) Mr. Jones bought two more adult tickets than children’s tickets. #1 11x+7y= 76 so x=5 & y =3 sufficient #2 x=2y insufficient IMO A _________________ If you liked my solution then please give Kudos. Kudos encourage active discussions. Re: Mr. Jones spends$ 76 on movie tickets for a group of adults and child   [#permalink] 22 Mar 2019, 01:44
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