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Mr. Jones spends $ 76 on movie tickets for a group of adults and child

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Mr. Jones spends $ 76 on movie tickets for a group of adults and child  [#permalink]

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New post 03 Jan 2016, 13:48
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A
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D
E

Difficulty:

  55% (hard)

Question Stats:

64% (01:56) correct 36% (01:39) wrong based on 86 sessions

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Mr. Jones spends $ 76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase?

(1) Adult movie tickets cost $ 11 each and children’s movie tickets cost $ 7 each.
(2) Mr. Jones bought two more adult tickets than children’s tickets.

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Re: Mr. Jones spends $ 76 on movie tickets for a group of adults and child  [#permalink]

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New post 03 Jan 2016, 16:31
Bunuel wrote:
Mr. Jones spends $ 76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase?

(1) Adult movie tickets cost $ 11 each and children’s movie tickets cost $ 7 each.
(2) Mr. Jones bought two more adult tickets than children’s tickets.


(1) 11a + 7c=76 --> \(c=\frac{76-11a}{7}\), so we have here a unique combination a=5, c=3 Sufficient
(2) Clearly not sufficient, as we don't know the total amount

Answer A
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Re: Mr. Jones spends $ 76 on movie tickets for a group of adults and child  [#permalink]

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New post 07 Jan 2016, 06:36
BrainLab wrote:
Bunuel wrote:
Mr. Jones spends $ 76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase?

(1) Adult movie tickets cost $ 11 each and children’s movie tickets cost $ 7 each.
(2) Mr. Jones bought two more adult tickets than children’s tickets.


(1) 11a + 7c=76 --> \(c=\frac{76-11a}{7}\), so we have here a unique combination a=5, c=3 Sufficient
(2) Clearly not sufficient, as we don't know the total amount

Answer A



We know the total 76$ so D
5 & 3 resp
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Re: Mr. Jones spends $ 76 on movie tickets for a group of adults and child  [#permalink]

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New post 07 Jan 2016, 07:19
paidlukkha wrote:
BrainLab wrote:
Bunuel wrote:
Mr. Jones spends $ 76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase?

(1) Adult movie tickets cost $ 11 each and children’s movie tickets cost $ 7 each.
(2) Mr. Jones bought two more adult tickets than children’s tickets.


(1) 11a + 7c=76 --> \(c=\frac{76-11a}{7}\), so we have here a unique combination a=5, c=3 Sufficient
(2) Clearly not sufficient, as we don't know the total amount

Answer A



We know the total 76$ so D
5 & 3 resp



Hi,
you may know the total amount and the info that there are 2 more adult tickets than children's tickets..
but till we know some relation or values of individual tickets, we cannot say anything about the final number..
you are unconsciously carrying forward the info of statement 1 to statement 2..
so 2 is not sufficient..
A
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Re: Mr. Jones spends $ 76 on movie tickets for a group of adults and child  [#permalink]

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New post 07 Jan 2016, 09:45
Hi,
you may know the total amount and the info that there are 2 more adult tickets than children's tickets..
but till we know some relation or values of individual tickets, we cannot say anything about the final number..
you are unconsciously carrying forward the info of statement 1 to statement 2..
so 2 is not sufficient..
A[/quote]

No
1$ each
37 adults
39 children
76$
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Re: Mr. Jones spends $ 76 on movie tickets for a group of adults and child  [#permalink]

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New post 07 Jan 2016, 10:14
Answer is A.

With statement B, we don't know the prices of each ticket.
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Re: Mr. Jones spends $ 76 on movie tickets for a group of adults and child  [#permalink]

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New post 22 Mar 2019, 01:44
Bunuel wrote:
Mr. Jones spends $ 76 on movie tickets for a group of adults and children. How many children’s tickets did he purchase?

(1) Adult movie tickets cost $ 11 each and children’s movie tickets cost $ 7 each.
(2) Mr. Jones bought two more adult tickets than children’s tickets.


#1
11x+7y= 76
so
x=5 & y =3 sufficient
#2
x=2y
insufficient
IMO A
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Re: Mr. Jones spends $ 76 on movie tickets for a group of adults and child   [#permalink] 22 Mar 2019, 01:44
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Mr. Jones spends $ 76 on movie tickets for a group of adults and child

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