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Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all the votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast? (A) 10% (B) 12% (C) 15% (D) 17% (E) 20%

It is D

Assuming he got 40 of the 100 votes. He needs 10 more==> 10/60X100=16.66

given (40/100)(V) = 942568 where V is the total number of votes

=> (60V/100) is the remaining and we were asked to find what % of remaining votes does he need to win

( he needs 10% more votes to win)

=> \((p/100)(60V/100) = 10V/100\)

=> p = 17%

Answer is D.

if you look carefully we dont even have to use the 942568 any where in our calculation. Hope it helps.

tonebeeze wrote:

I got this problem correct using brute force algebra, but the process took to long. What is the most efficient method to solve problems like this one?

Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?

Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]

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24 Apr 2014, 23:19

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Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]

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27 Dec 2015, 19:11

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Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]

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07 Jul 2016, 22:14

Curly05 wrote:

Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?

A. 10% B. 12% C. 15% D. 17% E. 20%

No need to use the given number of votes..

The total votes are = 100%

Kramer = 40%

Opponent(Remaining Votes) = 60%

Kramer needs 10% of the total votes to become 50%..we will take this out from Opponent's votes

Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]

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08 Jul 2016, 05:19

Curly05 wrote:

Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?

A. 10% B. 12% C. 15% D. 17% E. 20%

Given number is irrelevant here.

Let's say total number of votes = n and additional number of votes required = x

x= .10n (.50n-.40n)

Remaining votes = .60n

if .60n is 100% then .10n = .10*100/.60= 17% (Approximately)

D is the answer
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Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]

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24 Jul 2017, 07:33

Hello from the GMAT Club BumpBot!

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Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]

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08 Sep 2017, 20:11

No need to get bogged down with calculations. Since it is a % problem. Let total votes be 100 40% of 100=40 Left=60(100-40) Now we need a % of 60 so that the no obtained can be added to 40 to make it 50 or 50% of the total votes. 10% of 60=6 15% of 60=9 17% of 60=10.2-Answer(question says approx value)

Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]

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09 Sep 2017, 04:23

It is a very tricky question the number of voters seem to suggest a lot of calculation but we do not have to use that number Kramer got 40% of the votes Remaining votes =60%

Now to get 50 percent he must get 10 percent more So so 10/60*100=16.66 or 17% hence D is the answer
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