GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 20 Apr 2019, 09:26

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Mrs. Pearson has 4 boys and 5 girls in her class.

Author Message
TAGS:

### Hide Tags

Manager
Joined: 14 Oct 2015
Posts: 249
GPA: 3.57
Mrs. Pearson has 4 boys and 5 girls in her class.  [#permalink]

### Show Tags

19 Jul 2017, 08:49
1
00:00

Difficulty:

15% (low)

Question Stats:

86% (01:05) correct 14% (01:13) wrong based on 83 sessions

### HideShow timer Statistics

Mrs. Pearson has 4 boys and 5 girls in her class. She is to choose 2 boys and 2 girls to serve on her grading committee. If one girl and one boy leave before she can make a selection, then how many unique committees can result from the information above?

A - 9
B - 12
C - 18
D - 22
E - 120

_________________
Please hit Kudos if this post helped you inch closer to your GMAT goal.
Procrastination is the termite constantly trying to eat your GMAT tree from the inside.
There is one fix to every problem, working harder!
Math Expert
Joined: 02 Aug 2009
Posts: 7568
Re: Mrs. Pearson has 4 boys and 5 girls in her class.  [#permalink]

### Show Tags

19 Jul 2017, 09:10
jedit wrote:
Mrs. Pearson has 4 boys and 5 girls in her class. She is to choose 2 boys and 2 girls to serve on her grading committee. If one girl and one boy leave before she can make a selection, then how many unique committees can result from the information above?

A - 9
B - 12
C - 18
D - 22
E - 120

Hi,

I really dont know the purpose of" 1 boy n 1 girl leave"?
Does it make Q complicated- NO.
Hard-NO...
Tests something extra- NO... Just subtracting 1 from 4 n 5..

So there are 3 boys and 4girls left.... Choose 2 from each.
3C2*4C2=3*6=18

C
_________________
Intern
Joined: 30 Dec 2016
Posts: 20
Location: India
GMAT 1: 480 Q22 V22
Re: Mrs. Pearson has 4 boys and 5 girls in her class.  [#permalink]

### Show Tags

20 Jul 2017, 00:23
Should be C(18),
Picking 2 boys from 3 boys=3C2
Picking 2 girls from 4 girls=4C2
Total arrangements=3C2*4C2=3*6= 18

Posted from my mobile device
_________________
Dread it, Run from it, Destiny still arrives.
Target Test Prep Representative
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2825
Re: Mrs. Pearson has 4 boys and 5 girls in her class.  [#permalink]

### Show Tags

25 Jul 2017, 11:52
jedit wrote:
Mrs. Pearson has 4 boys and 5 girls in her class. She is to choose 2 boys and 2 girls to serve on her grading committee. If one girl and one boy leave before she can make a selection, then how many unique committees can result from the information above?

A - 9
B - 12
C - 18
D - 22
E - 120

Since one girl and one boy leave before she can make a selection, she now has 4 girls and 3 boys left. Thus, we need to determine the number of ways to select 2 girls from 4 and 2 boys from 3.

The girls can be selected in 4C2 = (4 x 3)/2! = 6 ways and the boys can be selected in 3C2 = 3 ways. Thus, the total number of ways to select the committee is 6 x 3 = 18 ways.

_________________

# Jeffrey Miller

Jeff@TargetTestPrep.com
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

Re: Mrs. Pearson has 4 boys and 5 girls in her class.   [#permalink] 25 Jul 2017, 11:52
Display posts from previous: Sort by