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If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of a^n, what is the value of a ?

(1) a^n = 64
(2) n = 6

answer

hi i believe that the answer to this question has to be C
As A provides us with no concrete by which we can jump to the solution as it can be 2^6 or 4^3, both will give us the same solution
Selecting b dosen t not solve our question
the answer lies in C where in we can add up both the parts and arrive at asolution..
Do correct me if I am wrong

(1) a^n = 64
Sufficient. If a is 2, so a^n = 2^6 which is a factor of 1 * 2^7 * 3^2 *5 * 7. But if a = 4, then a^n = 4^3 which is also a factor of 1 * 2^7 * 3^2 *5 * 7. So we do not know the value of a.

(2) n = 6 tells us a = 2, so a^n = 2^6 which is a factor of 1 * 2^7 * 3^2 *5 * 7. Sufficient.

(1) a^n = 64 Sufficient. If a is 2, so a^n = 2^6 which is a factor of 1 * 2^7 * 3^2 *5 * 7. But if a = 4, then a^n = 4^3 which is also a factor of 1 * 2^7 * 3^2 *5 * 7. So we do not know the value of a.

Ans: B

I lost track that we were finding a. So according to A. a could be 2, 4 or 8. But according to B it is only 2.