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# My Experimental Prob. Question - For Golfers

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Director
Joined: 14 Oct 2003
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Location: On Vacation at My Crawford, Texas Ranch
My Experimental Prob. Question - For Golfers [#permalink]

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26 Nov 2003, 10:27
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I just thought up another question - you'll like this question if you're a golfer:

see revised question at the bottom.

Last edited by Titleist on 26 Nov 2003, 13:31, edited 7 times in total.

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GMAT Instructor
Joined: 07 Jul 2003
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Location: New York NY 10024
Schools: Haas, MFE; Anderson, MBA; USC, MSEE

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26 Nov 2003, 11:09
If you have 9 golfers with mean 12 with 0 as lowest and 24 as highest, it is impossible to get a stdev as low as 3 -- even if all of the other golfers were at the mean.
_________________

Best,

AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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Director
Joined: 14 Oct 2003
Posts: 583

Kudos [?]: 56 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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26 Nov 2003, 11:30
AkamaiBrah wrote:
If you have 9 golfers with mean 12 with 0 as lowest and 24 as highest, it is impossible to get a stdev as low as 3 -- even if all of the other golfers were at the mean.

Thanks! You were absolutely right. I made a revision as a result. Kudos Akamai!

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Director
Joined: 14 Oct 2003
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Kudos [?]: 56 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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26 Nov 2003, 13:30
A "Two some" is to be chosen out of an eligible pool of 9 golfers to play at a charity tournament. The best golfer in the pool has a handicap of 0 while the worst golfer has a handicap of 24. No two golfers have the same handicap. The median and mean handicap are 12 and each of the golfer's handicap from worst to best can be derived from the sequence Tn=Tn-1 + 3. What is the probability that the median handicap of the golfers chosen from the pool will have a median handicap less than 15?

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Director
Joined: 13 Nov 2003
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26 Nov 2003, 13:44
as far as I understand the question you have normal distribution with mean and median 12, SD 4, since 15 < 1 SD from mean and you want the median score to be less than 15, you have 50%+34%=84% probability

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Director
Joined: 14 Oct 2003
Posts: 583

Kudos [?]: 56 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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26 Nov 2003, 14:30
Forget the Standard Deviation - i took that out. You should be able to figure out all the handicaps based on the sequence formula. I'll let you take it from there!

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Director
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27 Nov 2003, 05:46
although i can not understand your exp prob very well think that this is what you mean: the median means that it is in the middle between any 2 golfers selected, so 2 of 9 in 36 ways, if select 24( we can not select 21,18,15,12,9 cause the median is>15) -3 ways, 23-3ways, 18-4 ways, 3 out of 6 (0,3,6,9,12,)=20 ways or total 30 ways, or30/36= 5/6 or 83%..hope makes sense

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27 Nov 2003, 05:46
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