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# n/2

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Manager
Joined: 05 Jul 2006
Posts: 196

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21 Aug 2006, 12:24
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

...

Last edited by lan583 on 11 Feb 2007, 08:54, edited 1 time in total.

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Director
Joined: 06 May 2006
Posts: 791

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21 Aug 2006, 12:39
A.

1) [(n/3)*74.5 + (2n/3)*70]/n. n can be eliminated, hence we can have the answer.

2) Insufficient.
_________________

Uh uh. I know what you're thinking. "Is the answer A, B, C, D or E?" Well to tell you the truth in all this excitement I kinda lost track myself. But you've gotta ask yourself one question: "Do I feel lucky?" Well, do ya, punk?

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CEO
Joined: 20 Nov 2005
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Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008

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21 Aug 2006, 15:36
A

St1: (n/3) * 74.5 + (2n/3) * 70 = n * A, where A is average of all
So A can be calculated.

St2: We don't know total numer of people.
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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Manager
Joined: 20 Mar 2006
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21 Aug 2006, 20:38
lan583 wrote:
...

(1) (Sum of height of n/3 ppl) / (n/3) = 6ft 2.5 in
(Sum of height of n/3 ppl) = n*6ft2.5in/3 --------(a)

(Sum of height of 2n/3 ppl) / (2n/3) = 5ft 10 in
(Sum of height of 2n/3 ppl) = 2n*5ft10in/3-----(b)

From (a) & (b)
sum heights of n ppl= (Sum of height of n/3 ppl)+(Sum of height of 2n/3 ppl)

Hence we can cal avg

(2) Insuff No information abt n

Hence A

Heman

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Re: GMATPrep   [#permalink] 21 Aug 2006, 20:38
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