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# N and P

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Manager
Joined: 16 Feb 2010
Posts: 225

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18 Mar 2011, 02:45
00:00

Difficulty:

(N/A)

Question Stats:

57% (01:23) correct 43% (00:52) wrong based on 7 sessions

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think answer is C but not sure? any help?
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n and p.jpg [ 66.85 KiB | Viewed 1481 times ]

Director
Status: Impossible is not a fact. It's an opinion. It's a dare. Impossible is nothing.
Affiliations: University of Chicago Booth School of Business
Joined: 03 Feb 2011
Posts: 900

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18 Mar 2011, 02:50
Confirmed C

Posted from my mobile device
Manager
Joined: 16 Feb 2010
Posts: 225

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18 Mar 2011, 03:05
gmat1220 wrote:
Confirmed C

Posted from my mobile device

thanks
Manager
Joined: 05 Jan 2011
Posts: 177

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18 Mar 2011, 08:28
zisis wrote:
gmat1220 wrote:
Confirmed C

Posted from my mobile device

thanks 8-)

Statement 1. n+1>0 ie n>-1 ...we do not know sign of p....Insufficient

Statement 2. np>0 ie both n and p are positive or both are negative.... Insufficient

1+2 ...from st1 n is integer and greater than -1 ..therefore it should be 0,1,2,3,4...... ie positive number
from st2 if n is positive p is also positive ......So p should be positive as we know n>-1

C
Intern
Joined: 18 Mar 2011
Posts: 1

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18 Mar 2011, 18:55
Quote:

Statement 1. n+1>0 ie n>-1 ...we do not know sign of p....Insufficient

Statement 2. np>0 ie both n and p are positive or both are negative.... Insufficient

1+2 ...from st1 n is integer and greater than -1 ..therefore it should be 0,1,2,3,4...... ie positive number
from st2 if n is positive p is also positive ......So p should be positive as we know n>-1

C

+1 to u
Director
Joined: 01 Feb 2011
Posts: 755

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18 Mar 2011, 19:11
1.Not sufficient.

n > -1

n could be 0,1,2....

2. Not Sufficient
n>0,p>0 or n<0,p<0
so this is not enough to determine the sign of p.

together

n is not equal to 0 (otherwise 2 wont be true.) .
n can be any of the following => n>0 => p>0

1,2,3....
Re: N and P   [#permalink] 18 Mar 2011, 19:11
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