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Newman biked around a square garden at the speeds of 20 miles/hour

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Newman biked around a square garden at the speeds of 20 miles/hour  [#permalink]

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New post 01 Jan 2019, 08:22
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A
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Question Stats:

62% (02:01) correct 38% (01:49) wrong based on 35 sessions

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Newman biked around a square garden at the speeds of 20 miles/hour, 30 miles/hour, 40 miles/hour,
and 60 miles/hour along the four sides. What was his average speed for the entire ride?

A. 32
B. 35
C. 37.5
D. 40
E. 50

Source: Experts Global

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Re: Newman biked around a square garden at the speeds of 20 miles/hour  [#permalink]

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New post 01 Jan 2019, 09:37
pushpitkc wrote:
Newman biked around a square garden at the speeds of 20 miles/hour, 30 miles/hour, 40 miles/hour,
and 60 miles/hour along the four sides. What was his average speed for the entire ride?

A. 32
B. 35
C. 37.5
D. 40
E. 50

Source: Experts Global

If the fastest speed 60mph took one hour, then

60 mph - 1 h
40 mph - 1,5 h
30 mph - 2 h
20 mph - 3 h

Total miles travelled:
60 times 4 =240 miles
Time spent 7,5 h


240/7,5=480/15 =32 >A

Posted from my mobile device
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Newman biked around a square garden at the speeds of 20 miles/hour  [#permalink]

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New post 01 Jan 2019, 09:41
\(Average_{Speed}\) = \(\frac{Total Distance}{Time}\)
Let the distance be D.
Since it is a square, the total distance is 4D
\(Average_{Speed}\) = 4D/{D/20+D/30+D/40+D/60} = 4D/15D*120 = 8*4 = 32

A is the answer.
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Re: Newman biked around a square garden at the speeds of 20 miles/hour  [#permalink]

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New post 01 Jan 2019, 10:18
pushpitkc wrote:
Newman biked around a square garden at the speeds of 20 miles/hour, 30 miles/hour, 40 miles/hour,
and 60 miles/hour along the four sides. What was his average speed for the entire ride?

A. 32
B. 35
C. 37.5
D. 40
E. 50

Source: Experts Global


Since newman biked around a square garden so distances travelled is the same in each case.

So average speed will the arithmetic mean of the 4 speed. i.e (20+30+40+60)/4 = 150/4 = 37.5 (C)
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Re: Newman biked around a square garden at the speeds of 20 miles/hour  [#permalink]

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New post 01 Jan 2019, 10:27
shuvodip04 wrote:
pushpitkc wrote:
Newman biked around a square garden at the speeds of 20 miles/hour, 30 miles/hour, 40 miles/hour,
and 60 miles/hour along the four sides. What was his average speed for the entire ride?

A. 32
B. 35
C. 37.5
D. 40
E. 50

Source: Experts Global


Since newman biked around a square garden so distances travelled is the same in each case.

So average speed will the arithmetic mean of the 4 speed. i.e (20+30+40+60)/4 = 150/4 = 37.5 (C)

That is the trap answer. You miss out on the time spent per side is not the same

Posted from my mobile device
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Wish my good luck for 700 before Christmas!
If you think my post provided any help, please give +1 kudos, it helps a lot! <3

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Joined: 05 Oct 2017
Posts: 61
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GPA: 4
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Re: Newman biked around a square garden at the speeds of 20 miles/hour  [#permalink]

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New post 01 Jan 2019, 10:50
ErikLewe wrote:
shuvodip04 wrote:
pushpitkc wrote:
Newman biked around a square garden at the speeds of 20 miles/hour, 30 miles/hour, 40 miles/hour,
and 60 miles/hour along the four sides. What was his average speed for the entire ride?

A. 32
B. 35
C. 37.5
D. 40
E. 50

Source: Experts Global


Since newman biked around a square garden so distances travelled is the same in each case.

So average speed will the arithmetic mean of the 4 speed. i.e (20+30+40+60)/4 = 150/4 = 37.5 (C)

That is the trap answer. You miss out on the time spent per side is not the same

Posted from my mobile device


oh yes.a blunder on my part.thanks..

The solution will be Total distance/total time

If length of each side = d
Average speed = 4d / (d/20+d/30+d/40+d/60) = 4/((6+4+3+2)/120) = 4 * 120/15 = 4*8 =32 hence A)
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Re: Newman biked around a square garden at the speeds of 20 miles/hour   [#permalink] 01 Jan 2019, 10:50
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Newman biked around a square garden at the speeds of 20 miles/hour

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