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Re: sum of digits of a two digit number [#permalink]

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06 Nov 2012, 08:59

D = 10x + y

S = 10x^2 + y^2

S-D --> (10x^2 + y^2) - (10x + y) = 27 --> 10x (x-1) + y (y+1) = 27 ---->>> and then further calculation but I'm stuck here! So I have to agree with maybe Bunuel knowwwsssss!

Re: Number S is obtained by squaring the sum of digits of a two [#permalink]

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12 Nov 2013, 12:57

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feruz77 wrote:

Number S is obtained by squaring the sum of digits of a two digit number D. If difference between S and D is 27, then the two digit number D is:

A. 24 B. 54 C. 34 D. 45 E. 25

This problem doesn't need a direct method once you realise that S = 27+D Also, S is a perfect square. Thus, we can eliminate D and E straightaway, as the units digit in both the cases will be 2. Only option B gives a perfect square.
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Re: Number S is obtained by squaring the sum of digits of a two [#permalink]

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25 Feb 2016, 12:28

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