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Re: Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]
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Mountain14 wrote:
Of the 100 athletes at a soccer club, 40 play defense and 70 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between

A. 10 to 20
B. 10 to 40
C. 30 to 40
D. 30 to 70
E. 40 to 70


Fill the attached table and ull get the answer in less than a min

Since max number of athletes who can play defense s only 40, after filling the table u can conclude that the (c) 30 to 40 is the answer
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Re: Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]
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HarveyS wrote:
Of the 100 athletes at a soccer club, 40 play defense and 70 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between

A. 10 to 20
B. 10 to 40
C. 30 to 40
D. 30 to 70
E. 40 to 70


Here is how you can think about it:

We are given the minimum value of "Neither" and we need to find the minimum and maximum value of "Both".

Total = A + B - Both + Neither

Both = 40 + 70 - 100 + Neither

Both = 10 + Neither

Minimum value of Neither is 20.

Maximum value of Neither will be obtained when "defense" circle in inside the "midfield" circle. So 100 - 70 = 30 would be Neither.

So minimum value of Both is 10+20 = 30 and maximum value is 10+30 = 40.

Answer (C)
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Re: Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]
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HarveyS wrote:
Of the 100 athletes at a soccer club, 40 play defense and 70 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between

A. 10 to 20
B. 10 to 40
C. 30 to 40
D. 30 to 70
E. 40 to 70


We can use the formula for overlapping sets:

Total = Midfield + Defense - Both + Neither

Now, using the least number of athletes who play neither position (20 players), we have:

100 = 70 + 40 - x + 20

100 = 130 - x

x = 30

So 30 is the least number of athletes who play both positions. However, the number of athletes who play both positions can’t exceed the number of athletes who play defense. Therefore, the greatest number of athletes who play both positions is 40.

Answer: C
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Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]
https://gmatclub.com/forum/of-the-400-m ... 23692.html
Same technique as Bunuel's Table Matrix here.
Just be aware of the constraint that the max value can be 40 instead of 70
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Of the 100 athletes at a soccer club, 40 play defense and 70 [#permalink]
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