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Of the 60 animals on a certain farm, 2/3 are either pigs or

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Manager
Joined: 13 Mar 2006
Posts: 73
Of the 60 animals on a certain farm, 2/3 are either pigs or [#permalink]

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04 May 2006, 22:31
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Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many of the animals are cows?
(1) The farm has more than twice as many cows as it has pigs.
(2) The farm has more than 12 pigs.
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VP
Joined: 06 Jun 2004
Posts: 1053
Location: CA

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04 May 2006, 23:44
C?

There are 27 cows

(1) Many combinations of cows/pigs would satisfy this equation
(2) Clearly infufficient

(1) + (2) P = 13, C = 27 ==> OK
P = 14, C = 26 ==> (1) FAILS
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Director
Joined: 10 Oct 2005
Posts: 718

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05 May 2006, 01:07
Of the 60 animals on a certain farm, 2/3 are either pigs or cows
Not clear what about the 1/3?
E for me
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Director
Joined: 24 Oct 2005
Posts: 659
Location: London

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05 May 2006, 02:50
Why is it not A?

2/3 are either pigs or cows.

P + C = 40

Statement 1 gives that there are twice the no of cows

ie. C = 2P

from this we can get the no of cows.
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Joined: 07 Jul 2004
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05 May 2006, 02:57
2/3(60) = 40 either pigs or cows
# of pigs = P
# of cows = 40-p

St1:
40-p = 2p

Can solve for p, then solve for # of cows. Sufficient.

St2:
Sufficient. We know p and therefore can calculate # of cows, which is 40-p.

Ans D

** I assume the remaining 1/3 are neither pigs nor cows.
Director
Joined: 24 Oct 2005
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05 May 2006, 03:07
ywilfred wrote:
2/3(60) = 40 either pigs or cows
# of pigs = P
# of cows = 40-p

St1:
40-p = 2p

Can solve for p, then solve for # of cows. Sufficient.

St2:
Sufficient. We know p and therefore can calculate # of cows, which is 40-p.

Ans D

** I assume the remaining 1/3 are neither pigs nor cows.

But from statement 2 we only know that no of pigs is MORE than 12. It can be 13, 14 or even 39.
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Joined: 06 Jun 2004
Posts: 1053
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05 May 2006, 20:54
remgeo wrote:
Why is it not A?

2/3 are either pigs or cows.

P + C = 40

Statement 1 gives that there are twice the no of cows

ie. C = 2P

from this we can get the no of cows.

The statement says 'more than twice as many'
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Manager
Joined: 27 Mar 2006
Posts: 136

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05 May 2006, 22:36
I say E...since exact number can not be determined...all we know is it is more than a certain value
05 May 2006, 22:36
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