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Of the 800 employees in a certain company, 70% have serviced [#permalink]

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04 Feb 2012, 13:24

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Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

Ans 200

Step by step:

\(0.7*800=560\) employees have serviced more than 10 years;

We are told that after \(y\) of those employees leave the company the # of employees who have serviced more than 10 years (\(560-y\)) become 60% of a new total, which will be \(800-y\), so: \(0.6*(800-y)=(560-y)\) --> \(y=200\).

Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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05 Feb 2012, 04:19

Ans is 200 employees let y employees retire so now 560-y employees remain. So total no of employees becomes 800-y 560-y/800-y = 60/100 on solving we get y =200

Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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02 Dec 2012, 00:10

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Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. What is y if the 10 years employees become 60% of the total employees?

Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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27 Aug 2015, 10:53

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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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11 Nov 2016, 09:39

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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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11 Nov 2016, 11:59

arps wrote:

Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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11 Nov 2016, 12:08

arps wrote:

Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

Number of employees serving more than 10 years is changing; However, number of employees working less than 10 years is not changing. So we can take that into account for easy calculations.

30% of 800 (employees working less than 10 years)= 240

After y employees left, the number of employees working less than 10 years increased to 40%.

If 40% is 240, than 100%= 600

There is difference of 200 employees between then and now (800-600). Hence 200 is the answer.
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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12 Nov 2016, 01:00

Bunuel wrote:

arps wrote:

Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

Ans 200

Step by step:

\(0.7*800=560\) employees have serviced more than 10 years;

We are told that after \(y\) of those employees leave the company the # of employees who have serviced more than 10 years (\(560-y\)) become 60% of a new total, which will be \(800-y\), so: \(0.6*(800-y)=(560-y)\) --> \(y=200\).

Hope it's clear.

please tell me when I went wrong... my understanding is bit different on this question. 70% are more than 10 years ..... 30% are 10 and less than 10 years. 70%of 800 = 560 30%of 800 = 240

Now Y are going to retire and these Y come in 70% group, resulting in something ... what is that .. 240 becomes 60% of the total now Here total has to be the decreased number .... then only 60% possible ...

so 60% of (800-y) = 240 ..... why are we taking 560-y as 60%

Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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29 Jul 2017, 09:32

arps wrote:

Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

40% of the total = 240 ------ divide each side by 4 10% of the total = 60--------- multiply by 10 Total = 600 over 10 years who did not retire = 600 - 240 = 360 over 10 years who did retire (y) = 70%(800) -360 = 200