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# Of the 800 employees in a certain company, 70% have serviced

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Of the 800 employees in a certain company, 70% have serviced [#permalink]

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04 Feb 2012, 13:24
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Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

[Reveal] Spoiler:

Last edited by Bunuel on 04 Feb 2012, 13:29, edited 1 time in total.
Edited the question

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04 Feb 2012, 13:28
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arps wrote:
Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

Ans 200

Step by step:

$$0.7*800=560$$ employees have serviced more than 10 years;

We are told that after $$y$$ of those employees leave the company the # of employees who have serviced more than 10 years ($$560-y$$) become 60% of a new total, which will be $$800-y$$, so: $$0.6*(800-y)=(560-y)$$ --> $$y=200$$.

Hope it's clear.
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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05 Feb 2012, 04:19
Ans is 200 employees
let y employees retire so now 560-y employees remain. So total no of employees becomes 800-y
560-y/800-y = 60/100
on solving we get y =200

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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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02 Dec 2012, 00:10
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Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. What is y if the 10 years employees become 60% of the total employees?

Solution:

TOTAL 10 YRS
Original: 800 560
New: 800-y 560-y

560-y = .6 (800 -y)
560-y = 480 - .6y
80 = .4y
800/4 = y
y= 200

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Of the 800 employees in a certain company, 70% have serviced [#permalink]

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19 Jun 2014, 03:36
Total Employees = 800

70% = 560

> than 10 Yrs ......... Others ............ Total

560 ..........................240 ..................... 800

Total y employees retire; new figures would be

560-y ................................. 240 ....................... 800-y

Given that post retirement of y employees; > than 10yrs employees would be 60% of total

This also means that the other employees are 40% of the total (Reason behind this step is to have the variable y only at one side of the equation)

Setting up the equation

$$240 = \frac{40}{100} (800-y)$$

y = 200

ARPS: Can you please provide the OA for this question?
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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19 Jun 2014, 03:45
PareshGmat wrote:
Total Employees = 800

70% = 560

> than 10 Yrs ......... Others ............ Total

560 ..........................240 ..................... 800

Total y employees retire; new figures would be

560-y ................................. 240 ....................... 800-y

Given that post retirement of y employees; > than 10yrs employees would be 60% of total

This also means that the other employees are 40% of the total (Reason behind this step is to have the variable y only at one side of the equation)

Setting up the equation

$$240 = \frac{40}{100} (800-y)$$

y = 200

ARPS: Can you please provide the OA for this question?

The OA is 200. It's given under the spoiler in the original post.
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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27 Aug 2015, 10:53
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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11 Nov 2016, 09:39
Hello from the GMAT Club BumpBot!

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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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11 Nov 2016, 11:59
arps wrote:
Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

[Reveal] Spoiler:

Total employees = 800

More than 10 years = 560 ; Less than/Upto 10 years = 140

$$\frac{560 - y}{800-y} = \frac{60}{100}$$

Or, $$\frac{560 - y}{800-y} = \frac{3}{5}$$

Or, 2800 - 5y = 2400 - 3y

Or, 400 = 2y

Or, y =200

Hence, answer will be y =200....

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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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11 Nov 2016, 12:08
arps wrote:
Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

[Reveal] Spoiler:

Number of employees serving more than 10 years is changing; However, number of employees working less than 10 years is not changing. So we can take that into account for easy calculations.

30% of 800 (employees working less than 10 years)= 240

After y employees left, the number of employees working less than 10 years increased to 40%.

If 40% is 240, than 100%= 600

There is difference of 200 employees between then and now (800-600). Hence 200 is the answer.
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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12 Nov 2016, 01:00
Bunuel wrote:
arps wrote:
Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

Ans 200

Step by step:

$$0.7*800=560$$ employees have serviced more than 10 years;

We are told that after $$y$$ of those employees leave the company the # of employees who have serviced more than 10 years ($$560-y$$) become 60% of a new total, which will be $$800-y$$, so: $$0.6*(800-y)=(560-y)$$ --> $$y=200$$.

Hope it's clear.

please tell me when I went wrong... my understanding is bit different on this question.
70% are more than 10 years ..... 30% are 10 and less than 10 years.
70%of 800 = 560
30%of 800 = 240

Now Y are going to retire and these Y come in 70% group, resulting in something ... what is that .. 240 becomes 60% of the total now
Here total has to be the decreased number .... then only 60% possible ...

so 60% of (800-y) = 240 ..... why are we taking 560-y as 60%

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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]

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29 Jul 2017, 09:32
arps wrote:
Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?

[Reveal] Spoiler:

40% of the total = 240 ------ divide each side by 4
10% of the total = 60--------- multiply by 10
Total = 600
over 10 years who did not retire = 600 - 240 = 360
over 10 years who did retire (y) = 70%(800) -360 = 200

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Re: Of the 800 employees in a certain company, 70% have serviced   [#permalink] 29 Jul 2017, 09:32
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