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Of the 800 employees in a certain company, 70% have serviced [#permalink]
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04 Feb 2012, 13:24
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Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?
Last edited by Bunuel on 04 Feb 2012, 13:29, edited 1 time in total.
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]
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05 Feb 2012, 04:19
Ans is 200 employees let y employees retire so now 560y employees remain. So total no of employees becomes 800y 560y/800y = 60/100 on solving we get y =200



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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]
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Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. What is y if the 10 years employees become 60% of the total employees? Solution: TOTAL 10 YRS Original: 800 560 New: 800y 560y 560y = .6 (800 y) 560y = 480  .6y 80 = .4y 800/4 = y y= 200 Answer: 200
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Of the 800 employees in a certain company, 70% have serviced [#permalink]
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19 Jun 2014, 03:36
Total Employees = 800 70% = 560 > than 10 Yrs ......... Others ............ Total560 ..........................240 ..................... 800 Total y employees retire; new figures would be 560y ................................. 240 ....................... 800y Given that post retirement of y employees; > than 10yrs employees would be 60% of total This also means that the other employees are 40% of the total (Reason behind this step is to have the variable y only at one side of the equation)Setting up the equation \(240 = \frac{40}{100} (800y)\) y = 200 Answer = 200 ARPS: Can you please provide the OA for this question?
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]
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19 Jun 2014, 03:45
PareshGmat wrote: Total Employees = 800
70% = 560
> than 10 Yrs ......... Others ............ Total
560 ..........................240 ..................... 800
Total y employees retire; new figures would be
560y ................................. 240 ....................... 800y
Given that post retirement of y employees; > than 10yrs employees would be 60% of total
This also means that the other employees are 40% of the total (Reason behind this step is to have the variable y only at one side of the equation)
Setting up the equation
\(240 = \frac{40}{100} (800y)\)
y = 200
Answer = 200
ARPS: Can you please provide the OA for this question? The OA is 200. It's given under the spoiler in the original post.
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]
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11 Nov 2016, 11:59
arps wrote: Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees? Total employees = 800 More than 10 years = 560 ; Less than/Upto 10 years = 140 \(\frac{560  y}{800y} = \frac{60}{100}\) Or, \(\frac{560  y}{800y} = \frac{3}{5}\) Or, 2800  5y = 2400  3y Or, 400 = 2y Or, y =200 Hence, answer will be y =200....
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]
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11 Nov 2016, 12:08
arps wrote: Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees? Number of employees serving more than 10 years is changing; However, number of employees working less than 10 years is not changing. So we can take that into account for easy calculations. 30% of 800 (employees working less than 10 years)= 240 After y employees left, the number of employees working less than 10 years increased to 40%. If 40% is 240, than 100%= 600 There is difference of 200 employees between then and now (800600). Hence 200 is the answer.
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Re: Of the 800 employees in a certain company, 70% have serviced [#permalink]
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12 Nov 2016, 01:00
Bunuel wrote: arps wrote: Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. When is y if the 10 years employees become 60% of the total employees?
Ans 200 Step by step: \(0.7*800=560\) employees have serviced more than 10 years; We are told that after \(y\) of those employees leave the company the # of employees who have serviced more than 10 years (\(560y\)) become 60% of a new total, which will be \(800y\), so: \(0.6*(800y)=(560y)\) > \(y=200\). Hope it's clear. please tell me when I went wrong... my understanding is bit different on this question. 70% are more than 10 years ..... 30% are 10 and less than 10 years. 70%of 800 = 560 30%of 800 = 240 Now Y are going to retire and these Y come in 70% group, resulting in something ... what is that .. 240 becomes 60% of the total now Here total has to be the decreased number .... then only 60% possible ... so 60% of (800y) = 240 ..... why are we taking 560y as 60%




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