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# Of the following integers which is the closest approximation

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Of the following integers which is the closest approximation [#permalink]

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14 May 2010, 07:34
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Of the following integers, which is the closest approximation to $$(\sqrt{2} + \sqrt{5})^2$$?

A. 7
B. 10
C. 13
D. 15
E. 17
[Reveal] Spoiler: OA

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15 May 2010, 02:05
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vannbj wrote:
Of the following integers, which is the closest approximation to $$(\sqrt{2} + \sqrt{5})^2$$?

7
10
13
15
17

How do you do this without a calculator?

$$(\sqrt{2} + \sqrt{5})^2=2+2*\sqrt{2}*\sqrt{5}+5=7+2\sqrt{10}$$ --> $$\sqrt{10}\approx{3}$$ --> $$7+2\sqrt{10}\approx{7+6}=13$$

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23 Apr 2013, 00:14
Of the following integers what is the closest approximation to ( squareroot 2 + squareroot 5 )^ 2 ?

1.7
2.10
3.13
4.15
5.17
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23 Apr 2013, 00:35
$$(a+b)^2=(2+5+2\sqrt{10})=2+5+2*3=13$$

C
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23 Apr 2013, 03:48
kabilank87 wrote:
Of the following integers what is the closest approximation to ( squareroot 2 + squareroot 5 )^ 2 ?

1.7
2.10
3.13
4.15
5.17

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Re: Of the following integers which is the closest approximation [#permalink]

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16 Jul 2014, 13:00
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Re: Of the following integers which is the closest approximation [#permalink]

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30 Mar 2015, 04:11
Bunuel wrote:
vannbj wrote:
Of the following integers, which is the closest approximation to $$(\sqrt{2} + \sqrt{5})^2$$?

7
10
13
15
17

How do you do this without a calculator?

$$(\sqrt{2} + \sqrt{5})^2=2+2*\sqrt{2}*\sqrt{5}+5=7+2\sqrt{10}$$ --> $$\sqrt{10}\approx{3}$$ --> $$7+2\sqrt{10}\approx{7+6}=13$$

How did you get 2[square_root]10? I expanded the original equation and went from [square_root]20 to 2[square_root]5.

Thanks for your help

More specifically this is how I approached it:

2 + [square_root]10 + [square_root]10 + 5
7 + [square_root]20
7 + [square_root]4 [square_root]5
7 + 2[square_root]5
9 + [square_root]5
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Re: Of the following integers which is the closest approximation [#permalink]

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30 Mar 2015, 04:15
joaomario wrote:
Bunuel wrote:
vannbj wrote:
Of the following integers, which is the closest approximation to $$(\sqrt{2} + \sqrt{5})^2$$?

7
10
13
15
17

How do you do this without a calculator?

$$(\sqrt{2} + \sqrt{5})^2=2+2*\sqrt{2}*\sqrt{5}+5=7+2\sqrt{10}$$ --> $$\sqrt{10}\approx{3}$$ --> $$7+2\sqrt{10}\approx{7+6}=13$$

How did you get 2[square_root]10? I expanded the original equation and went from [square_root]20 to 2[square_root]5.

Thanks for your help

More specifically this is how I approached it:

2 + [square_root]10 + [square_root]10 + 5
7 + [square_root]20
7 + [square_root]4 [square_root]5
7 + 2[square_root]5
9 + [square_root]5

I'm not exactly sure what you are doing there...

You should apply $$(a+b)^2=a^2+2ab+b^2$$.

Hope it helps.
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Re: Of the following integers which is the closest approximation [#permalink]

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31 Mar 2015, 11:14
vannbj wrote:
Of the following integers, which is the closest approximation to $$(\sqrt{2} + \sqrt{5})^2$$?

A. 7
B. 10
C. 13
D. 15
E. 17

(sqrt(2) + sqrt(5))^2 =2 + 2*sqrt(2)*sqrt(5) + 5
= 7 + 2*sqrt(10)
= 7 + 2*3 (approximated to sqrt(9))
= 13
Hence option (C).

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Re: Of the following integers which is the closest approximation [#permalink]

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16 May 2016, 07:01
Hello from the GMAT Club BumpBot!

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Re: Of the following integers which is the closest approximation   [#permalink] 16 May 2016, 07:01
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# Of the following integers which is the closest approximation

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