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# Of the following, which is the closest approximation to 32/0.256^(1/2)

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Re: Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink]
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Bunuel
Of the following, which is the closest approximation to $$\frac{32}{\sqrt{0.256}}=$$ ?

A. 20
B. 30
C. 60
D. 200
E. 600

PS21251

We can save a lot of time by recognizing 0.256 ≈ 0.25, and that √0.25 = 0.5 (since 0.5² = 0.25)

So, we get: $$\frac{32}{\sqrt{0.256}}≈ \frac{32}{\sqrt{0.25}} ≈ \frac{32}{0.5} ≈ 64$$

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Re: Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink]
Bunuel
Of the following, which is the closest approximation to $$\frac{32}{\sqrt{0.256}}=$$ ?

A. 20
B. 30
C. 60
D. 200
E. 600

PS21251

$$0.50*0.50 = 0.25$$

$$\frac{32}{\sqrt{0.256}}$$

= $$\frac{32}{0.50}$$

= $$64$$

~ $$60$$, Answer must be (C)
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Re: Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink]
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Re: Of the following, which is the closest approximation to 32/0.256^(1/2) [#permalink]
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