Hi All,

You'll likely find it easiest to handle this calculation in 'pieces'

This question lays out the following restrictions:

1) 3-digit numbers greater than 700

2) All digits are NON-0 and DIFFERENT

3) The number must be ODD.

Let's start with the 700s...

1st digit is 7 = 1 option

3rd digit must be ODD, but NOT 7 = 4 options

2nd digit must differ from the other two digits and not be 0 = 7 options

(1)(4)(7) = 28 numbers in the 700s

Now, the 800s...

1st digit is 8 = 1 option

3rd digit must be ODD = 5 options

2nd digit must differ from the other two digits and not be 0 = 7 options

(1)(5)(7) = 35 numbers in the 800s

Finally, the 900s; the math here works the same as the 700s...

1st digit is 9 = 1 option

3rd digit must be ODD, but NOT 9 = 4 options

2nd digit must differ from the other two digits and not be 0 = 7 options

(1)(4)(7) = 28 numbers in the 900s

28+35+28 = 91

Final Answer:

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Rich

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