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# OG PS - 184

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Senior Manager
Joined: 25 Nov 2006
Posts: 333

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Schools: St Gallen, Cambridge, HEC Montreal
OG PS - 184 [#permalink]

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19 Jun 2007, 11:01
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Hello there,

OG PS 184 is

If the two-digit integers M and N are positive and have the same digits, but in reverse order, which of the following CANNOT be the sum of M and N?

A - 181
B - 165
C - 121
D - 99
E - 44

I'm interested in the method to solve this. Can someone please help me?

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Senior Manager
Joined: 03 Jun 2007
Posts: 376

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19 Jun 2007, 11:59
It is actually a simple question. Answer is A

Let the numbers be 10x + y and 10y + x
So their sum is 11(x+y)
only 181 is not a multiple of 11

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VP
Joined: 08 Jun 2005
Posts: 1144

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19 Jun 2007, 12:24
lumone wrote:
dahcrap wrote:
It is actually a simple question. Answer is A

Let the numbers be 10x + y and 10y + x
So their sum is 11(x+y)
only 181 is not a multiple of 11

How did you come to 10x + y and 10y + x?

in every two digit number (i.e xy) the first digit (i.e x) equal to x*10 and the second digit equal to y*1

81 = 8*10+1*1
55 = 5*10+5*1
6545 = 6*1000+5*100+4*10+5*1

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Senior Manager
Joined: 21 Jun 2006
Posts: 282

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20 Jun 2007, 13:44
A
All other nos can be split up into two nos with both digits being equal

Kudos [?]: 143 [0], given: 0

20 Jun 2007, 13:44
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# OG PS - 184

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