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Old McDonald divided his hens evenly between his two daughters, Pamela

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Old McDonald divided his hens evenly between his two daughters, Pamela  [#permalink]

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New post 29 Nov 2016, 01:17
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B
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  15% (low)

Question Stats:

90% (02:22) correct 10% (02:05) wrong based on 84 sessions

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Old McDonald divided his hens evenly between his two daughters, Pamela and Paris. After one week, during which the flock of Pamela had grown by 60 hens and the flock of Paris had grown by 10 hens, both daughters sold all of their hens. Pamela sold each hen for 80 cents and Paris sold each hen for 30 cents. How many hens did old McDonald originally have, if Pamela's revenue from selling her flock was four times as much as Paris' revenue?

A. 160
B. 180
C. 200
D. 220
E. 240

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Re: Old McDonald divided his hens evenly between his two daughters, Pamela  [#permalink]

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New post 29 Nov 2016, 02:20
pamela = x hens
paris = x hens

after increase

pamela = x+60
Paris = x+10

Pamela revenue is four times paris revenue

(x+60)80 = 4 (x+10)30

80x+4800 = 120x + 1200

2x+120 = 3x+30

x=90
2x= 180

Answer (B)
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Re: Old McDonald divided his hens evenly between his two daughters, Pamela  [#permalink]

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New post 29 Nov 2016, 11:18
Bunuel wrote:
Old McDonald divided his hens evenly between his two daughters, Pamela and Paris. After one week, during which the flock of Pamela had grown by 60 hens and the flock of Paris had grown by 10 hens, both daughters sold all of their hens. Pamela sold each hen for 80 cents and Paris sold each hen for 30 cents. How many hens did old McDonald originally have, if Pamela's revenue from selling her flock was four times as much as Paris' revenue?

A. 160
B. 180
C. 200
D. 220
E. 240


Let Old McDonald had 2x hens...

So, each of Pamela and Paris got x hens each..

Now, \(( x + 60 )80 = 4( x + 10 )30\)

Or, \(80x + 4800 = 120x + 1200\)

Or, \(3600 = 40x\)

Or, x = 90

So, Old McDonald had 180 hens, answer will be (B)
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Re: Old McDonald divided his hens evenly between his two daughters, Pamela  [#permalink]

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New post 29 Nov 2016, 13:09
Original # of hens = 2x

Pamela = x
Paris = x

Pamela after a week = x+60
Paris after a week = x+10

Revenue from Pamela i.e. 0.8(x+60) = 4*Revenue from Paris
=> 0.8*(x+60) = 4*0.3*(x+10) => x = 90

Therefore original = 2x = 180.
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Re: Old McDonald divided his hens evenly between his two daughters, Pamela  [#permalink]

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New post 22 Feb 2018, 17:43
Bunuel wrote:
Old McDonald divided his hens evenly between his two daughters, Pamela and Paris. After one week, during which the flock of Pamela had grown by 60 hens and the flock of Paris had grown by 10 hens, both daughters sold all of their hens. Pamela sold each hen for 80 cents and Paris sold each hen for 30 cents. How many hens did old McDonald originally have, if Pamela's revenue from selling her flock was four times as much as Paris' revenue?

A. 160
B. 180
C. 200
D. 220
E. 240


We can let the total number of hens = n and create the equation:

80(n/2 + 60) = 4[30(n/2 + 10)]

40n + 4800 = 60n + 1200

3600 = 20n

180 = n

Answer: B
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Re: Old McDonald divided his hens evenly between his two daughters, Pamela   [#permalink] 22 Feb 2018, 17:43
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