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I agree that the level of a question depends on real gmat test takers' results. But imho this tag on a forum shouldnt be assessed by the level of only current gmatclub users, since perhaps current guys can be math genious or vise versa dummies like me:)

So , i wanted Bunuel to assess the level of a question, using his experience. He solved lots of gmat questions and knows well all ins&outs of this test. I feel better when i see his assessment rather than the one generated by some unknown to me users.

Anyways, i dont insist on anything. It is ur forum and ur rules. I just expressed my thoughts as a user and hope didnt offend anyone.

Posted from my mobile device

Dear LalaB,

As Bunuel said, the question of offend does not arise. When someone asks me the level of a question, I usually look at the question and judge according to my experience and move on. I do not go into details of why it is an inaccurate exercise. In this case I got into an explanation because you are a seasoned and valued participant of this community - with people like that, your mind instinctively tries to go out of its way to help, discuss and give what you think is the best answer (I might have offended someone else now!) I actually did not go to the question to judge what level it is before putting my response because that was irrelevant to the point I was trying to make.
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On a certain road 10% of the motorists exceed the posted spe [#permalink]

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14 Aug 2015, 06:00

Quote:

On a certain road 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?

(A) 10 1/2% (B) 12 1/2% (C) 15% (D) 22% (E) 30%

I don't know whether it's just me, but I find the wording of this question to be horrible. I actually got it right and came to 12,5%. Nevertheless, at least from my understanding the question looks for something completely different, namely - ''What percent of the motorists on the road exceed the posted speed limit?". So the question is rather looking for a comparison between motorists that exceed the limit and such that don't. Here we rather compare those that got tickets to the ones that didn't.

Am I the only one with this doubt or is it a way that exam makers want to confuse you?

Thanks!
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Thank you very much for reading this post till the end! Kudos?

Last edited by bgpower on 17 Aug 2015, 23:37, edited 1 time in total.

On a certain road 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?

(A) 10 1/2% (B) 12 1/2% (C) 15% (D) 22% (E) 30%

I don't know whether it's just me, but I find the wording of this question to be horrible. I actually got it right and came to 12,5%. Nevertheless, at least from my understanding the question looks for something completely different, namely - ''What percent of the motorists on the road exceed the posted speed limit?". So the question is rather looking for a comparison between motorists that exceed the limit and such that don't. Here we rather compare those that got tickets to the ones that didn't.

Am I the only one with this doubt or is it a way that exam makers what to confuse you?

Thanks!

The question is fine.

Some fraction of the motorists exceed the speed limit. Say x%. We need to find x%.

Some of these x% motorists get speeding tickets (say y%) and others do not. Anyone who gets a speeding ticket (belongs to y%) must belong to these x%.

You are given that y% of x% of Total motorists = 10% of Total motorists (people who exceed the limit and get tickets)

Also, 20% of x% do not get tickets. This means 80% of x% do get tickets.

This 80% of x% of Total= 10% of Total (we are already given)

Re: On a certain road 10% of the motorists exceed the posted spe [#permalink]

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31 Oct 2015, 11:24

1

This post received KUDOS

let's say we have 100 motorists 10 received tickets for speeding. we know that 0.2 of the total people who were speeding did not receive tickets. that means that 10+0.2y = y, where y stands for all people who were speeding. 10 = 0.8y -> rewrite 10*10/8 = 100/8 = 25/2 = 12.5. B.

Re: On a certain road 10% of the motorists exceed the posted spe [#permalink]

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25 Nov 2016, 12:44

VeritasPrepKarishma wrote:

bgpower wrote:

Quote:

On a certain road 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?

(A) 10 1/2% (B) 12 1/2% (C) 15% (D) 22% (E) 30%

I don't know whether it's just me, but I find the wording of this question to be horrible. I actually got it right and came to 12,5%. Nevertheless, at least from my understanding the question looks for something completely different, namely - ''What percent of the motorists on the road exceed the posted speed limit?". So the question is rather looking for a comparison between motorists that exceed the limit and such that don't. Here we rather compare those that got tickets to the ones that didn't.

Am I the only one with this doubt or is it a way that exam makers what to confuse you?

Thanks!

The question is fine.

Some fraction of the motorists exceed the speed limit. Say x%. We need to find x%.

Some of these x% motorists get speeding tickets (say y%) and others do not. Anyone who gets a speeding ticket (belongs to y%) must belong to these x%.

You are given that y% of x% of Total motorists = 10% of Total motorists (people who exceed the limit and get tickets)

Also, 20% of x% do not get tickets. This means 80% of x% do get tickets.

This 80% of x% of Total= 10% of Total (we are already given)

So x% of Total = 12.5% of Total

Hi, I would agree with bgpower , the language is extremely confusing (at least to me)- the questions asks for "What percent of the motorists on the road exceed the posted speed limit?" In my opinion, the question suggests that it is asking about the percent of motorists, who exceed the speed limit regardless of who was named on the ticket and who wasn't. I mean some people won't pay fine but they did in fact still exceeded the speed limit. How to deal with such confusions? Wouldn't it be better formulated question had it asked about the percentage of motorist who received a ticket.

On a certain road 10% of the motorists exceed the posted speed limit and receive speeding tickets, but 20% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?

A. 10.5% B. 12.5% C. 15% D. 22% E. 30%

We can use the Double Matrix Method to solve this question.

This technique can be used for most questions featuring a population in which each member has two characteristics associated with it.

Here, we have a population of motorists, and the two characteristics are: - speeder (S) or non-speeder (~S) - get ticket (T) or not get ticket (~T)

Since this question concerns percents (instead of actual values), let's assign a "nice" value to the total number of motorists in this population. Let's say there are 100 motorists.

So, to begin, our matrix looks like this.

10 percent of the motorists exceed the posted speed limit and receive speeding tickets The top left box is for motorists who speed and receive speeding tickets. So, 10% of the entire population will be in this box.

20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. The motorists referred to here are those who go in the top right box. Unfortunately, we don't know the total number of speeders, so we can't find 20% of that value. So, let's let x = the total number of speeders.

Now we can deal with this: 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. In other words, 20% of x will go in the top right box.

At this point, we know that the sum of the top 2 boxes is x. So, we can write: 10 + 0.2x = x (now solve) Arrange: 10 = 0.8x Divide: 10/0.8 = x 12.5 = x

Since x represents the total number of speeders, we know that 12.5 out of 100 motorists speed. In other words, 12.5% of motorists speed. Answer: B

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Last edited by GMATPrepNow on 17 Feb 2018, 11:07, edited 1 time in total.

I always get confuse with below question. I am not able to understand wordings of question. I searched question in GMAT club and found earlier posts are inactive. Could you please advise how to approach this question.

On a certain road 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit? (A) 10,5% (B) 12,5% (C) 15% (D) 22% (E) 30%

Hi,

Although this must have been already discussed, but since you want a way to go about such Qs..

Let the overall 100% be 100... So 10 exceed limit and get speeding ticket.

Now 20% exceed limit and do not get speeding ticket, MEANS remaining (100-20)% get speeding ticket..

The above info tells us that 80% of total exceeding limit=10.. So TOTAL= \(\frac{10*100}{80}\)= 12.5%

I always get confuse with below question. I am not able to understand wordings of question. I searched question in GMAT club and found earlier posts are inactive. Could you please advise how to approach this question.

On a certain road 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit? (A) 10,5% (B) 12,5% (C) 15% (D) 22% (E) 30%

We can also use the Double Matrix Method to solve this question.

This technique can be used for most questions featuring a population in which each member has two characteristics associated with it. Here, we have a population of motorists, and the two characteristics are: - speeder (S) or non-speeder (~S) - get ticket (T) or not get ticket (~T)

Since this question concerns percents (instead of actual values), let's assign a "nice" value to the total number of motorists in this population. Let's say there are 100 motorists.

So, to begin, our matrix looks like this.

10 percent of the motorists exceed the posted speed limit and receive speeding tickets The top left box is for motorists who speed and receive speeding tickets. So, 10% of the entire population will be in this box.

20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. The motorists referred to here are those who go in the top right box. Unfortunately, we don't know the total number of speeders, so we can't find 20% of that value. So, let's let x = the total number of speeders.

Now we can deal with this: 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. In other words, 20% of x will go in the top right box.

At this point, we know that the sum of the top 2 boxes is x. So, we can write: 10 + 0.2x = x (now solve) Arrange: 10 = 0.8x Divide: 10/0.8 = x 12.5 = x

Since x represents the total number of speeders, we know that 12.5 out of 100 motorists speed. In other words, 12.5% of motorists speed. Answer: B

On a certain road 10% of the motorists exceed the posted speed limit and receive speeding tickets, but 20% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?

A. 10.5% B. 12.5% C. 15% D. 22% E. 30%

We can let the total number of motorists = m and the number of motorists who exceed the speed limit = n. Thus, we need to determine the value of n/m x 100.

We are given that 10 percent (or 0.1m) of the motorists exceed the posted speed limit and receive speeding tickets.

We are also given that 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. Since we let n = the number of motorists who exceed the speed limit, 0.2n = the number of motorists who speed who do not receive a speeding ticket.

We can create the following equation:

number of motorists who exceed the limit = number of motorists who speed and get a ticket + number who speed but do not get a ticket

n = 0.1m + 0.2n

0.8n = 0.1m

8n = m

Thus n/m x 100 = n/(8n) x 100 = 1/8 x 100 = 12.5 percent.

Answer: B
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