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On a Monday in a certain restaurant, 20 percent of the 180 customers o

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Bunuel
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On a Monday in a certain restaurant, 20 percent of the 180 customers o [#permalink] New post   17 Feb 2016, 04:23
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On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%

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B
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KarishmaB
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Re: On a Monday in a certain restaurant, 20 percent of the 180 customers o [#permalink] New post   18 Feb 2016, 22:32
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Bunuel wrote:
On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%

Kudos for correct solution.


Looking at the options, you can arrive at the correct answer in a few seconds using the weighted average concepts.

20% ordered on Monday and 10% on Tuesday, so combined, the percentage would be between 10% and 20%. It would have been 15% exactly if number of customers on both the days were the same. But there were more customers on Monday so the average will tilt toward 20%. You have two options, 16% and 18%. Since the ratio of the number of customers on the two days is 180:120 = 3:2, 16% divides the length between 10% and 20% in the ratio 3:2.

Answer (B)
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Re: On a Monday in a certain restaurant, 20 percent of the 180 customers o [#permalink] New post   18 Feb 2016, 04:31
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Bunuel wrote:
On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%

Kudos for correct solution.



20% of 180= 36

10% of 120=12

Total =48

percent for 2 days combined =48/300 ≈ 50/300=1/6 =0.1666. so it should be less than 0.1666 so it is 16%

Another approch 48/300= 48/(3*100)= 16/100=0.16

Answer:B
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Re: On a Monday in a certain restaurant, 20 percent of the 180 customers o [#permalink] New post   14 Apr 2018, 07:55
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Bunuel wrote:
On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%

Kudos for correct solution.


On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special.
10% of 180 = 18
So, 20% of 180 = 36
So, 36 people ordered the daily special on MONDAY

On Tuesday, only 10 percent of the 120 customers ordered the special.
10% of 120 = 12
So, 12 people ordered the daily special on TUESDAY

For the two days combined, what percent of the customers ordered the daily special?
TOTAL number of people who ordered the daily special = 36 + 12 = 48 people
TOTAL number of customers for the two days = 180 + 120 = 300

So 48/300 of the customers ordered the special.
Our job is to rewrite 48/300 as a PERCENT. Here's one approach:
Take: 48/300
Divide top and bottom by 3 to get the EQUIVALENT fraction 16/100
16/100 = 16%

Answer: B

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Brent
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Re: On a Monday in a certain restaurant, 20 percent of the 180 customers o [#permalink] New post   23 Feb 2016, 03:30
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Bunuel wrote:
On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%

Kudos for correct solution.

Just solving for the numbers should take you to the answers easily here.

Monday: 20% of 180 ordered daily special.
Therefore 36 ordered daily special.

Tuesday: 10% of 120 ordered daily special
Therefore 12 people ordered daily special

Total daily special = 48
Total people on Monday and Tuesday = 180 + 120 = 300

Percentage of people who ordered daily special = (48/300)*100 = 16%
Option B
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Re: On a Monday in a certain restaurant, 20 percent of the 180 customers o [#permalink] New post   25 Apr 2018, 16:44
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Bunuel wrote:
On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?

A. 15%
B. 16%
C. 18%
D. 23%
E. 30%


On the first day 0.2 x 180 = 36 customers ordered the special.

On the second day 0.1 x 120 = 12 ordered the special.

We combine the data for the two days. Thus, (36 + 12)/(180 + 120) = 48/300 = 0.16 = 16% of the customers ordered the special.

Answer: B
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Re: On a Monday in a certain restaurant, 20 percent of the 180 customers o [#permalink] New post   20 Sep 2022, 09:23
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Re: On a Monday in a certain restaurant, 20 percent of the 180 customers o [#permalink]
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