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on a number line, the distance between x and y is greater

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Intern
Joined: 21 Jan 2007
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on a number line, the distance between x and y is greater [#permalink]

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09 Jul 2007, 12:11
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on a number line, the distance between x and y is greater than the distance between x and z. Does z lie between x and y on the number line?

a. xyz <o
b. xy < 0

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Senior Manager
Joined: 03 Jun 2007
Posts: 376

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09 Jul 2007, 12:58
I see this as C. Will provide detailed explainations if it is right

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Director
Joined: 26 Feb 2006
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Re: gmatprep - DS question. [#permalink]

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09 Jul 2007, 15:40
dmittal wrote:
on a number line, the distance between x and y is greater than the distance between x and z. Does z lie between x and y on the number line?

a. xyz <o
b. xy < 0

got E.

a: all three or any one of them could be -ve. nsf.
b: either one is +ve or -ve and Z too. nsf.

a+b: from a and b, now we know z is +ve. if so, x is also +ve because z is close to x and y is -ve. buy z could be any side of x.

suppose: if y = -5 and x = 4, z could be 3 or 5.

So E.

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GMAT Club Legend
Joined: 07 Jul 2004
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Location: Singapore

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09 Jul 2007, 19:17
Using St1:
xyz <0> either all three are negative or one is negative.
If all negative, could be y = -6, x = -1, z = -1/2, or y = -6, x = -1, z = -3
If one is negative, could be y = -1, x = 3, z = 4 or y = -1, x = 3, z = 2
Insufficient.

Using St2:
xy < 0 only tells us one of x or y is negative. nothing about z. Insufficient.

Using both, we know z must be positive. and either x or y must be negative. Could still be y = -1, x = 3, z = 4 or y = -1, x = 3, z = 2. Insufficient.

Ans E

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Manager
Joined: 07 Feb 2007
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Re: gmatprep - DS question. [#permalink]

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09 Jul 2007, 19:34
dmittal wrote:
on a number line, the distance between x and y is greater than the distance between x and z. Does z lie between x and y on the number line?

a. xyz <o
b. xy < 0

From the red part we know four cases:
(1)x<z<y; (2)y<z<x; (3)z<x<y; (4)y<x<z.

(a) (1), (2), (3), and (4) are all possible. insufficient;

(b) (1), (2), (3), and (4) are all possible. insufficient;

(a)+(b): 0<z;
(1) possible; x<0<z<y (comply)
(2) possible; y<0<z<y (comply)
(3) ruled out;
(4) possible: 0<y<x<z (uncomply)

E is the answer.

Last edited by wudy on 09 Jul 2007, 19:42, edited 4 times in total.

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Manager
Joined: 07 Feb 2007
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Re: gmatprep - DS question. [#permalink]

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09 Jul 2007, 19:35
why some characters were lost?

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Re: gmatprep - DS question.   [#permalink] 09 Jul 2007, 19:35
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