Last visit was: 24 Apr 2024, 18:51 It is currently 24 Apr 2024, 18:51

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Difficulty: Sub 505 Levelx   Distance/Rate Problemsx                  
Show Tags
Hide Tags
Math Expert
Joined: 02 Sep 2009
Posts: 92900
Own Kudos [?]: 618822 [29]
Given Kudos: 81588
Send PM
Most Helpful Reply
Math Expert
Joined: 02 Sep 2009
Posts: 92900
Own Kudos [?]: 618822 [13]
Given Kudos: 81588
Send PM
General Discussion
avatar
Intern
Intern
Joined: 24 Apr 2013
Posts: 44
Own Kudos [?]: 26 [1]
Given Kudos: 23
Location: United States
Send PM
Math Expert
Joined: 02 Sep 2009
Posts: 92900
Own Kudos [?]: 618822 [1]
Given Kudos: 81588
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
1
Kudos
Expert Reply
SaraLotfy wrote:
Hello Bunuel,

My initial thought was to choose D since I had the same solution process which you described.
But then I thought to myself that no where in the question or the statements was it mentioned that Mary drove at a constant rate.

I guess I got confused between the types of questions where I can use the total distance/ total time to get the average speed, and others where I have to compute each trip on its own to get the total average.

I'm not sure if you get my point on this? because I faced several problems where if I simply use total distance and total time, it would yield a wrong answer. Please help me to clarify this misunderstanding

Thanks


The question asks: what was the average speed at which she drove the 50 miles?

Now, the average speed equals to (total distance)/(total time) irrespective whether the distance was covered at a constant speed or not.
avatar
Intern
Intern
Joined: 23 Jun 2013
Posts: 28
Own Kudos [?]: 63 [0]
Given Kudos: 2
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
I'm still confused about 2nd option.
Case A:-
Travelled 30 miles in 30 mints. Speed =dist/time = 30/0.5= 60 mph
Travelled 20 miles in 24 mints. Speed = dist/time = 20/(2/5) = 50mph
Avg = 55mph

Case b:-
Travelled 30 miles in 20 mints. Speed = dist/time= 30/(1/3) = 90mph
Travelled 20 miles in 34mints. Speed = dist/time = 20/(34/60) = 35.3mph
Avg = (90+35.3)/2= 62.64mph

Now in both cases we are getting different avg speed. Please comment
Math Expert
Joined: 02 Sep 2009
Posts: 92900
Own Kudos [?]: 618822 [0]
Given Kudos: 81588
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
Expert Reply
Nilabh_s wrote:
I'm still confused about 2nd option.
Case A:-
Travelled 30 miles in 30 mints. Speed =dist/time = 30/0.5= 60 mph
Travelled 20 miles in 24 mints. Speed = dist/time = 20/(2/5) = 50mph
Avg = 55mph

Case b:-
Travelled 30 miles in 20 mints. Speed = dist/time= 30/(1/3) = 90mph
Travelled 20 miles in 34mints. Speed = dist/time = 20/(34/60) = 35.3mph
Avg = (90+35.3)/2= 62.64mph

Now in both cases we are getting different avg speed. Please comment


You are using info from (1) for (2).

In fact the second statement is very easy. We know that Mary drove 50 miles, and we need to find the average speed at which she drove those 50 miles. (2) says that she drove a total of 54 minutes (0.9 hours), thus \(average \ speed=\frac{total \ distance}{total \ time}=\frac{50}{0.9}\). Sufficient.

Hope it helps.
Target Test Prep Representative
Joined: 14 Oct 2015
Status:Founder & CEO
Affiliations: Target Test Prep
Posts: 18756
Own Kudos [?]: 22049 [1]
Given Kudos: 283
Location: United States (CA)
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
1
Kudos
Expert Reply
Bunuel wrote:
On a recent trip, Mary drove 50 miles. What was the average speed at which she drove the 50 miles?

(1) She drove 30 miles at an average speed of 60 miles per hour and then drove the remaining 20 miles at an average speed of 50 miles per hour.
(2) She drove a total of 54 minutes.


We are being tested on average speed. The formula for average speed is:

average speed = total distance/total time

We are given that the total distance is 50 miles, so we can substitute 50 miles into our formula.

average speed = 50/total time

Thus, if we can determine the total time, we can determine the average speed.

Statement One Alone:

She drove 30 miles at an average speed of 60 miles per hour and then drove the remaining 20 miles at an average speed of 50 miles per hour.

We are given that Mary first drove 30 miles at an average speed of 60 mph.

Since time = distance/rate, we can say:

time for the first 30 miles = 30/60 = ½ hour

We are also given that Mary drove the remaining 20 miles at an average speed of 50 miles per hour. Thus, we can say:

time for the remaining 20 miles = 20/50 = 2/5 hours

So we know that total time = ½ + 2/5 = 5/10 + 4/10 = 9/10 hours. Since we have the total time, we can determine average speed. Statement one is sufficient to answer question. We can eliminate answer choices B, C, and E.

Statement Two Alone:

She drove a total of 54 minutes.

We are given the total time, so statement two is also sufficient to answer the question.

The answer is D.
Intern
Intern
Joined: 01 Jan 2017
Posts: 26
Own Kudos [?]: 6 [0]
Given Kudos: 2
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
Hi!

How do you know that this is a 650 level question?
Math Expert
Joined: 02 Sep 2009
Posts: 92900
Own Kudos [?]: 618822 [0]
Given Kudos: 81588
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
Expert Reply
EliMan wrote:
Hi!

How do you know that this is a 650 level question?


Difficulty level (seen in tags) is calculated automatically based on the timer stats from the users which attempted the question. The difficulty level of this question is thus sub-600. As you can see 77% of the users attempting the question answered it correctly spending at average 01:39 minutes.
Retired Moderator
Joined: 19 Mar 2014
Posts: 817
Own Kudos [?]: 969 [0]
Given Kudos: 199
Location: India
Concentration: Finance, Entrepreneurship
GPA: 3.5
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
On a recent trip, Mary drove 50 miles. What was the average speed at which she drove the 50 miles?

\(Speed = \frac{Distance}{Time}\)

\(Avg. Speed = \frac{Total Distance}{Total Time}\)

As the question is asking for Average Speed and we are already aware of distance, which means if we get some information on - how much time Mary drove we will be able to calculate the average speed.

Note, only knowing time would be sufficient for us to determine if the sentence is sufficient or not. We need calculate the exact average speed as this is DS question.

(1) She drove 30 miles at an average speed of 60 miles per hour and then drove the remaining 20 miles at an average speed of 50 miles per hour.

As we are given two different speeds for two split of distances, we should be able to calculate the time taken for these two speeds which will be our total time taken.

As we will be able to calculate time, this statement should be sufficient.

Hence, (1) =====> is SUFFICIENT

(2) She drove a total of 54 minutes.

This directly gives us the total time taken.

Once again, this statement should be sufficient.

Hence, (2) =====> is SUFFICIENT

Hence, Answer is D
GMAT Club Legend
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6821
Own Kudos [?]: 29912 [1]
Given Kudos: 799
Location: Canada
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
1
Bookmarks
Expert Reply
Top Contributor
Bunuel wrote:
On a recent trip, Mary drove 50 miles. What was the average speed at which she drove the 50 miles?

(1) She drove 30 miles at an average speed of 60 miles per hour and then drove the remaining 20 miles at an average speed of 50 miles per hour.
(2) She drove a total of 54 minutes.


Target question: What was Mary's average speed for the 50-mile trip?
Average speed = (total distance)/(total travel time)
= (50 miles)/(total travel time)

As you can see, we need only determine the total travel time in order to answer the target question.

Statement 1: She drove 30 miles at an average speed of 60 miles per hour and then drove the remaining 20 miles at an average speed of 50 miles per hour.
For both parts of her journey, we COULD determine the travel time, so we COULD find the total travel time, which means we COULD calculate Mary's average speed
Since we COULD answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: She drove a total of 54 minutes.
Perfect! Her total travel time is 54 minutes, so we COULD calculate Mary's average speed
Since we COULD answer the target question with certainty, statement 2 is SUFFICIENT

Answer: D

Cheers,
Brent
Director
Director
Joined: 28 Sep 2018
Posts: 734
Own Kudos [?]: 559 [0]
Given Kudos: 248
GMAT 1: 660 Q48 V33 (Online)
GMAT 2: 700 Q49 V37
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
Bunuel EducationAisle can we use Allegation for (1) and get our answer?
Admitted - Which School Forum Moderator
Joined: 25 Oct 2020
Posts: 1131
Own Kudos [?]: 1047 [1]
Given Kudos: 630
Schools: Ross '25 (M$)
GMAT 1: 740 Q49 V42 (Online)
Send PM
On a recent trip, Mary drove 50 miles. What was the average [#permalink]
1
Kudos
Hoozan wrote:
Bunuel EducationAisle can we use Allegation for (1) and get our answer?

Hoozan Sorry, I am not Bunuel, but I would love to help you out-

Yes, you can get to the answer via "Allegation".
You will get the equation-

\(\frac{50-x}{x-60} = \frac{3}{2}\)

Upon solving you will \(x = 56 m/hr\)
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32656
Own Kudos [?]: 821 [0]
Given Kudos: 0
Send PM
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: On a recent trip, Mary drove 50 miles. What was the average [#permalink]
Moderator:
Math Expert
92900 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne