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Re: On a road trip, Kip drove one-quarter the distance at an average speed [#permalink]
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GMATPrepNow wrote:
On a road trip, Kip drove one-quarter the distance at an average speed of v miles per hour, one-quarter the distance at an average speed of 2v miles per hour, one-quarter the distance at 4v miles per hour, and one-quarter the distance at 8v miles per hour. In terms of v, what was Kip’s average speed (in miles per hour) for the entire trip?

A) 15/4v
B) 15v/4
C) 32v/15
D) 4v/15
E) 15v/32

*kudos for all correct solutions


We all know \(speed = \frac{distance}{time}\)

Let distance be x. Kip drove one-quarter each time and exactly 4 times. distance traveled each time is \(\frac{x}{4}\).

Total Time taken = Time taken for Quarter 1 + Time taken for Quarter 2 + Time taken for Quarter 3 + Time taken for Quarter 4
= \(\frac{x}{4v} + \frac{x}{4*2v} + \frac{x}{4*4v} + \frac{x}{4*8v}\)
= \(\frac{15x}{4*8v}\)

We also know that Avg Speed = \(\frac{Total Distance}{Total Time}\)
= \(\frac{x}{15x/4*8v}\)
= \(\frac{32v}{15}\)

Ans - C
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On a road trip, Kip drove one-quarter the distance at an average speed [#permalink]
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GMATPrepNow wrote:
On a road trip, Kip drove one-quarter the distance at an average speed of v miles per hour, one-quarter the distance at an average speed of 2v miles per hour, one-quarter the distance at 4v miles per hour, and one-quarter the distance at 8v miles per hour. In terms of v, what was Kip’s average speed (in miles per hour) for the entire trip?

A) 15/4v
B) 15v/4
C) 32v/15
D) 4v/15
E) 15v/32

*kudos for all correct solutions

Assign a value for speed \(v\), then choose a convenient number for distance, D.

\(v\) increases by powers of 2. I want integers.
Let \(v=1\)
\(2v=2\)
\(4v=4\)
\(8v=8\)


\(D=8\) for each leg will yield an integer for the time for all four legs.

Time, \(t=\frac{D}{v}\)

Time, \(Leg_1\): \(\frac{8}{1}=8\)
Time, \(Leg_2\): \(\frac{8}{2}=4\)
Time, \(Leg_3\): \(\frac{8}{4}=2\)
Time, \(Leg_4\): \(\frac{8}{8}=1\)


Total \(T: (8+4+2+1) = 15\)
Total \(D: (8*4) = 32\)

Ave speed = \(\frac{TotalD}{TotalT}=\frac{32}{15}\)

Use \(v=1\). We need the answer choice that yields \(\frac{32}{15}\)

Immediately eliminate A, B, and E. Wrong denominator.
(Per Answer A, 4 is not a factor of 15. Nor does (4*1) = 15)

C) 32v/15 = \(\frac{32}{15}\) KEEP

D) 4v/15 = \(\frac{4}{15}\) REJECT

Answer C
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Re: On a road trip, Kip drove one-quarter the distance at an average speed [#permalink]
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Alternative short approach :

Avg speed of 1st two and next two given speed shall be (2ab/a+b). ( since, distances covered are equal.)

= 2*v*2v/3v and 2*4v*8v/12v
= 4v/3 and 16v/3
again, finding the avg speed of two obtained avg speeds:
= (2 * 4v/3*16v/3) / 20v/3
Hence, 32v/15.
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Re: On a road trip, Kip drove one-quarter the distance at an average speed [#permalink]
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GMATPrepNow wrote:
On a road trip, Kip drove one-quarter the distance at an average speed of v miles per hour, one-quarter the distance at an average speed of 2v miles per hour, one-quarter the distance at 4v miles per hour, and one-quarter the distance at 8v miles per hour. In terms of v, what was Kip’s average speed (in miles per hour) for the entire trip?

A) 15/4v
B) 15v/4
C) 32v/15
D) 4v/15
E) 15v/32

*kudos for all correct solutions


Since we aren't told the total distance, let's assign a nice value to the distance.
Let's say 32 miles = TOTAL distance.
So, each quarter = 8 miles

Average speed = total distance/total travel time
So, we must find the travel time for EACH QUARTER and add them together.

Time = distance/speed, so:
Time spent driving v mph = 8/v = 8/v
Time spent driving 2v mph = 8/2v = 4/v
Time spent driving 4v mph = 8/4v = 2/v
Time spent driving 8v mph = 8/8v = 1/v

TOTAL travel time = 8/v + 4/v + 2/v + 1/v
= 15/v

Average speed = total distance/total travel time
= 32/(15/v)
= (32)(v/15)
= 32v/15

Answer: C

Cheers,
Brent
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Re: On a road trip, Kip drove one-quarter the distance at an average speed [#permalink]
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Re: On a road trip, Kip drove one-quarter the distance at an average speed [#permalink]
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