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On average, each member of Team B earned 3/5 as much as each member of

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On average, each member of Team B earned 3/5 as much as each member of  [#permalink]

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New post 19 Aug 2019, 10:52
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On average, each member of Team B earned 3/5 as much as each member of Team A last year. If Team B has 3/4 as many members as Team A, what fraction of the total earnings did Team A earn?

A. 1/4

B. 7/12

C. 3/5

D. 5/8

E. 20/29

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Re: On average, each member of Team B earned 3/5 as much as each member of  [#permalink]

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New post 19 Aug 2019, 11:02
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SajjadAhmad wrote:
On average, each member of Team B earned 3/5 as much as each member of Team A last year. If Team B has 3/4 as many members as Team A, what fraction of the total earnings did Team A earn?

A. 1/4

B. 7/12

C. 3/5

D. 5/8

E. 20/29


Given:
1.On average, each member of Team B earned 3/5 as much as each member of Team A last year.
2.Team B has 3/4 as many members as Team A.

Asked: What fraction of the total earnings did Team A earn?

Earning B = 3/5 Earning A
Members B = 3/4 Members A

Earnings B = Earnings B * Members B = \(\frac{3}{5} * \frac{3}{4}\) Earnings A * Members A = \(\frac{9}{20}\) Earnings A
Earnings A : Earnings B = 20 : 9
Earnings A/ Total = \(\frac{20}{29}\)

IMO E
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Re: On average, each member of Team B earned 3/5 as much as each member of  [#permalink]

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New post 20 Aug 2019, 00:36
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+ Each member of Team B earned 3/5 as much as each member of Team A last year.
Let say:
- each member team B earns 3x
- each member of Team A earns 5x
+ If Team B has 3/4 as many members as Team A
- team B has 3y members
- team A has 4y members
=> team B earn 3x*3y=9xy earnings
team A earn 5x*4y=20xy earnings
Fraction: 20/(20+9)=20/29
Answer: E
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Re: On average, each member of Team B earned 3/5 as much as each member of  [#permalink]

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New post 20 Aug 2019, 00:43
Kinshook wrote:
SajjadAhmad wrote:
On average, each member of Team B earned 3/5 as much as each member of Team A last year. If Team B has 3/4 as many members as Team A, what fraction of the total earnings did Team A earn?

A. 1/4

B. 7/12

C. 3/5

D. 5/8

E. 20/29


Given:
1.On average, each member of Team B earned 3/5 as much as each member of Team A last year.
2.Team B has 3/4 as many members as Team A.

Asked: What fraction of the total earnings did Team A earn?

Earning B = 3/5 Earning A
Members B = 3/4 Members A

[color=#5574b9]Earnings B = Earnings B * Members B = \(\frac{3}{5} * \frac{3}{4}\) Earnings A * Members A = \(\frac{9}{20}\) Earnings A
Earnings A : Earnings B = 20 : 9
Earnings A/ Total = \(\frac{20}{29}\)

IMO E




sir can u explain the colored part again please
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Re: On average, each member of Team B earned 3/5 as much as each member of  [#permalink]

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New post 20 Aug 2019, 11:24
SajjadAhmad wrote:
On average, each member of Team B earned 3/5 as much as each member of Team A last year. If Team B has 3/4 as many members as Team A, what fraction of the total earnings did Team A earn?

A. 1/4

B. 7/12

C. 3/5

D. 5/8

E. 20/29


Earning per member of team A = a, Total number of member in team A =m
Earning per member of team B = b, Total number of member in team B = n
So, b = 3/5*a
and n = 3/4 *m

Team A earning in fraction of total earning = am/(am+bn) = am/(am+(3/5)*a*(3/4)*m)
= am/(am+(9/20)*am)
= 1/(1+9/20)
=20/29
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Re: On average, each member of Team B earned 3/5 as much as each member of  [#permalink]

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New post 25 Aug 2019, 18:37
SajjadAhmad wrote:
On average, each member of Team B earned 3/5 as much as each member of Team A last year. If Team B has 3/4 as many members as Team A, what fraction of the total earnings did Team A earn?

A. 1/4

B. 7/12

C. 3/5

D. 5/8

E. 20/29


Let’s say that each member of team A earned an average of 5; then each member of team B earned an average of 3. If Team A has 4 members, then team B has 3 members.

Thus, Team A earned (5 x 4)/[(5 x 4)+(3 x 3)] = 20/29 of the total earnings of the two teams.

Answer: E
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Re: On average, each member of Team B earned 3/5 as much as each member of   [#permalink] 25 Aug 2019, 18:37
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