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# On her way home from work, Janet drives through several

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Manager
Joined: 25 Aug 2004
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Location: MONTREAL
On her way home from work, Janet drives through several [#permalink]

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10 Aug 2005, 09:38
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On her way home from work, Janet drives through several toobooths.

Is there a pair of these tollbooths that are less than 10 miles a part?

(1) The first tollbooth and the last tollbooth are 25 miles apart?

(2) Janet droves through 4 tollbooths on her way home from work?

A- Statement 1 Alone is sufficient
B- Statement 2 Alone is sufficient
C- Statement 1 and Statement 2 together are sufficient
D- Each statement alone is sufficient
E- None of these statements are sufficient

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SVP
Joined: 03 Jan 2005
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10 Aug 2005, 10:14
It's an obvious C. (4-1)*10=30>25
_________________

Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

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Senior Manager
Joined: 30 May 2005
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10 Aug 2005, 10:47
C it is for me. With 4 tollbooths, there must be 3 gaps.

g1 + g2 + g3 = 25, so at least one of them must be less than 10

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Manager
Joined: 31 Aug 2004
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11 Aug 2005, 11:11
C for me as well.

Consider 1) alone first. Since it only gives us the total distance between the first and last tollbooth, we cannot answer the question without knowing the number of tollbooth in between. Eliminate A) and D).

Consider 2) alone. We only know the number of toolbooth and without knowing the total distance in between, there is no way to asnwer the question. Eliminate B).

Consider 1) and 2) together and it can be figure out the distance between any 2 tollbooth. Eliminate E) and the answer is C).

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Senior Manager
Joined: 30 May 2005
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11 Aug 2005, 15:59
plz like to know the OA

agree that st 1 IS NOT SUFFICIENT
and st 2 NOT SUFFICIENT

but i will go for E if i am right i will explain why

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Manager
Joined: 09 Nov 2004
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13 Aug 2005, 16:04
It could be also possible that the gaps could be small and unequal.Hence, E.

What is the OA?
_________________

Thanks!

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Manager
Joined: 06 Aug 2005
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14 Aug 2005, 00:15
The answer is C, because the average distance between booths is 25/3 = 8.33, at least one of them must be shorter than that.

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14 Aug 2005, 00:15
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