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On Monday an item was marked up x percent. On Tuesday it was marked...

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Director
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On Monday an item was marked up x percent. On Tuesday it was marked...  [#permalink]

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New post 09 Oct 2018, 09:06
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E

Difficulty:

  35% (medium)

Question Stats:

67% (01:51) correct 33% (02:01) wrong based on 57 sessions

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On Monday an item was marked up x percent. On Tuesday it was marked down x percent. If the original price of the item was d dollars, which of the following correctly expresses the final price of the item after the markup and markdown?

A) \(d\)

B) \(\frac{d(x−100)}{10,000}\)

C) \(\frac{dx}{100}\)

D) \(100\)−\(\frac{d(x^2−10000)}{10,000}\)

E) \(\frac{d(10,000 − x^2)}{10,000}\)

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Re: On Monday an item was marked up x percent. On Tuesday it was marked...  [#permalink]

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New post 09 Oct 2018, 09:15
Price after markup= (d*(100+x))/100
Price after mark down= ((d*(100+x))/100)*(100-x)/100
Final price= d*(10000-x^2)/10000 [E]
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Re: On Monday an item was marked up x percent. On Tuesday it was marked...  [#permalink]

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New post 09 Oct 2018, 11:36
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Price after mark up = original price + marked up price
= d+(xd/100)
Price after mark down= {d+(xd/100)}-[(x/100)*{d+(xd/100)}]
= d-{(x^2*d)/10000}

Answer is E
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Re: On Monday an item was marked up x percent. On Tuesday it was marked...  [#permalink]

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New post 17 Dec 2018, 14:36
This is wrong, but why?

\(d(1+\frac{x}{100})(1-\frac{x}{100})\)

\(d(1-\frac{x^2}{10,000})\)
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Re: On Monday an item was marked up x percent. On Tuesday it was marked...   [#permalink] 17 Dec 2018, 14:36
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