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# On Monday an item was marked up x percent. On Tuesday it was marked...

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Director
Joined: 11 Feb 2015
Posts: 671
On Monday an item was marked up x percent. On Tuesday it was marked...  [#permalink]

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09 Oct 2018, 08:06
1
2
00:00

Difficulty:

35% (medium)

Question Stats:

66% (01:18) correct 34% (01:32) wrong based on 50 sessions

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On Monday an item was marked up x percent. On Tuesday it was marked down x percent. If the original price of the item was d dollars, which of the following correctly expresses the final price of the item after the markup and markdown?

A) $$d$$

B) $$\frac{d(x−100)}{10,000}$$

C) $$\frac{dx}{100}$$

D) $$100$$−$$\frac{d(x^2−10000)}{10,000}$$

E) $$\frac{d(10,000 − x^2)}{10,000}$$

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Manish

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Intern
Joined: 20 Feb 2018
Posts: 5
Re: On Monday an item was marked up x percent. On Tuesday it was marked...  [#permalink]

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09 Oct 2018, 08:15
Price after markup= (d*(100+x))/100
Price after mark down= ((d*(100+x))/100)*(100-x)/100
Final price= d*(10000-x^2)/10000 [E]
Intern
Joined: 29 Oct 2012
Posts: 4
Re: On Monday an item was marked up x percent. On Tuesday it was marked...  [#permalink]

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09 Oct 2018, 10:36
1
Price after mark up = original price + marked up price
= d+(xd/100)
Price after mark down= {d+(xd/100)}-[(x/100)*{d+(xd/100)}]
= d-{(x^2*d)/10000}

Manager
Joined: 15 Feb 2018
Posts: 156
Re: On Monday an item was marked up x percent. On Tuesday it was marked...  [#permalink]

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17 Dec 2018, 13:36
This is wrong, but why?

$$d(1+\frac{x}{100})(1-\frac{x}{100})$$

$$d(1-\frac{x^2}{10,000})$$
Re: On Monday an item was marked up x percent. On Tuesday it was marked... &nbs [#permalink] 17 Dec 2018, 13:36
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