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# On rainy mornings, Mo drinks exactly N cups of hot chocolate

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Senior Manager
Joined: 21 Oct 2013
Posts: 420
On rainy mornings, Mo drinks exactly N cups of hot chocolate  [#permalink]

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05 Aug 2014, 09:36
1
1
00:00

Difficulty:

45% (medium)

Question Stats:

72% (02:45) correct 28% (02:49) wrong based on 101 sessions

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On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 5 cups of tea. Last week Mo drank a total of 26 cups of tea and hot chocolate together. If during that week Mo drank 14 more tea cups than hot chocolate cups, then how many rainy days were there last week?

A. 2
B. 3
C. 4
D. 5
E. 6
Manager
Joined: 22 Feb 2009
Posts: 173
Re: On rainy mornings, Mo drinks exactly N cups of hot chocolate  [#permalink]

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05 Aug 2014, 16:30
5
goodyear2013 wrote:
On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 5 cups of tea. Last week Mo drank a total of 26 cups of tea and hot chocolate together. If during that week Mo drank 14 more tea cups than hot chocolate cups, then how many rainy days were there last week?

A. 2
B. 3
C. 4
D. 5
E. 6

T= the number of cups of tea
C= the number of cups of hot chocolate

T+C = 26 & T-C=14 -> T= 20. C=6.
Mo drinks 5 cups of tea a day then number of days that are not rainy = 20/5 = 4
So number of rainy days = 7-4 = 3
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Manager
Joined: 11 Jun 2014
Posts: 54
Concentration: Technology, Marketing
GMAT 1: 770 Q50 V45
WE: Information Technology (Consulting)
Re: On rainy mornings, Mo drinks exactly N cups of hot chocolate  [#permalink]

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05 Aug 2014, 21:11
I think this question is not correct, or ambiguous.. We do not the week they mean here is 5 day working week or 7 day week

see,
N+(N+14) = 26, --> N=6

so he had 20 cups of tea last week, that's 4 non-rainy days.. and he had N=6 cups of hot chocolate on exactly 1 day.. that only adds up to 5 days! We have no info of the other two days. Or am I missing something here?
Intern
Status: Applying This Year !
Joined: 06 Aug 2013
Posts: 8
Location: India
GMAT 1: 680 Q46 V38
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Re: On rainy mornings, Mo drinks exactly N cups of hot chocolate  [#permalink]

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05 Aug 2014, 22:32
sshrivats,

I think if they meant a working week they would have specifically said so. Since the question is about week here, i think its the obvious 7 day week.
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Joined: 27 Dec 2012
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Location: India
Concentration: General Management, Technology
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Re: On rainy mornings, Mo drinks exactly N cups of hot chocolate  [#permalink]

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05 Aug 2014, 23:45
sshrivats wrote:
I think this question is not correct, or ambiguous.. We do not the week they mean here is 5 day working week or 7 day week

see,
N+(N+14) = 26, --> N=6

so he had 20 cups of tea last week, that's 4 non-rainy days.. and he had N=6 cups of hot chocolate on exactly 1 day.. that only adds up to 5 days! We have no info of the other two days. Or am I missing something here?

The question has sufficient information. There is no need to compute the value of N
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SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
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Location: India
Concentration: General Management, Technology
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On rainy mornings, Mo drinks exactly N cups of hot chocolate  [#permalink]

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06 Aug 2014, 00:00
goodyear2013 wrote:
On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 5 cups of tea. Last week Mo drank a total of 26 cups of tea and hot chocolate together. If during that week Mo drank 14 more tea cups than hot chocolate cups, then how many rainy days were there last week?

A. 2
B. 3
C. 4
D. 5
E. 6

Refer diagram below:

Say "x" are the rainy days, so days without rain = 7-x ........... (1)

Tea consumption on each non-rainy day = 5 ............ (2)

Total consumption of tea + coffee = 26

If 14 more cups of tea is consumed, then coffee consumption$$= \frac{26-14}{2} = 6$$

Tea consumption = 6+14 = 20 ......... (3)

Total Tea Consumption = Tea consumption per day * No of days

(3) = (2) * (1)

20 = (7-x) * 5

x = 3

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On rainy mornings, Mo drinks exactly N cups of hot chocolate  [#permalink]

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11 Dec 2017, 06:36
goodyear2013 wrote:
On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 5 cups of tea. Last week Mo drank a total of 26 cups of tea and hot chocolate together. If during that week Mo drank 14 more tea cups than hot chocolate cups, then how many rainy days were there last week?

A. 2
B. 3
C. 4
D. 5
E. 6

last week Mo drinks 26 total tea and choco. combined

N*R + 5 *X= 26 ( eqn - 1 Given )
Where R is no. of rainy days and X is no. of non rainy days
Also we are given N + ( 14+N )= 26 -> So N = 6 and Total tea cups ( 14+N) =20 or 5* X = 20 or X= 4 i.e. Non rainy days = 4
Putting in eqn 1 , we get 6*R + 5*4 = 26 -> 6R =6 or R = 1
No. of rainy days should be 1
The values of N, R and X should satisfy eqn - 1
Feel question , leaves something more to be desired.
Please share your views/opinions as to why eqn - 1 is not absolutely necessary to be satisfied.
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On rainy mornings, Mo drinks exactly N cups of hot chocolate &nbs [#permalink] 11 Dec 2017, 06:36
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