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# On the 25th of November in 1990, John was trying to make a new plan fo

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On the 25th of November in 1990, John was trying to make a new plan fo  [#permalink]

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27 Jun 2016, 10:11
15
00:00

Difficulty:

85% (hard)

Question Stats:

42% (01:53) correct 58% (01:56) wrong based on 100 sessions

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On the 25th of November in 1990, John was trying to make a new plan for Jan 1991. However, he did not have a new calendar that included Jan 1991. Then, in order to match a new plan for Jan 1991, which of following months of 1990 should he look at?

A. March

B. April

C. May

D. June

E. July

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Re: On the 25th of November in 1990, John was trying to make a new plan fo  [#permalink]

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27 Jun 2016, 22:23
6
5
smartguy595 wrote:
On the 25th of November in 1990, John was trying to make a new plan for Jan 1991. However, he did not have a new calendar that included Jan 1991. Then, in order to match a new plan for Jan 1991, which of following months of 1990 should he look at?

A. March B. April C. May D. June E. July

Can someone explain how to solve this in easy approach!

You need to find the month which will replicate the month of Jan 1991. This will happen when the number of days between the 1st of that month and 1st Jan are a multiple of 7.
Each month has at least 28 days which is a multiple of 7.
Start from July (option (E)) - July has 3 additional days. August has 3. Sep has 2. Oct has 3. Nov has 2. Dec has 3.
3 + 3 + 2 + 3 + 2 + 3 = 16
June has 2 additional days so 16+2 = 18
May has 3 additional days so 18+3 = 21

Starting from May 1, the number of days is a multiple of 7 till Jan 1991 so Jan calendar will mirror the May calendar.

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Re: On the 25th of November in 1990, John was trying to make a new plan fo  [#permalink]

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27 Jun 2016, 10:57
Let us assume 31st of Dec, 1989 was a Sunday and 1st of Jan, 1990 was a Monday. As 1990 wasn't a leap year, so number of days in 1990 = 365.

Now 365 mod 7 = 1. That means, 365th day of the year 1990, i.e. 30/12/1990, was a Monday
(if [day of the year] mod 7 = 0 then its day will be same as 31st of Dec, 1989. ex. 7th Jan, 14th Jan and so on)
Similarly if [day of the year] mod 7 = 1 then its day will be same as 1st of Jan, 1990. ex 8th Jan, 15th Jan and so on)

As we now know 365th day of the year 1990, i.e. 30/12/1990, was a Monday, so 1st of Jan, 1991 will be a Tuesday.

Now, we have to find out which month among the options has 1st of that month as a Tuesday.

1st of March is 31(Jan)+28(Feb)+1 day of the year = 60. So, 60 mod 7 = 4. So, 1st of March was a Thursday.
So option A is out.

Option B.
1st of April is 31(Jan)+28(Feb)+31(March)+1 day of the year = 91. So 91 mod 7 = 0. So, 1st of April was a Sunday.
Option B is out.

Option C.
1st of May is 31(Jan)+28(Feb)+31(March)+30(April)+1 day of the year = 121. So 120 mod 7 = 2. So, 1st of May was a Tuesday.
Hence, we have got our answer.

Answer C. Day of 1st of May, 1990 is same as Day of 1st of Jan, 1991.

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Re: On the 25th of November in 1990, John was trying to make a new plan fo  [#permalink]

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02 Nov 2017, 14:31
1
VeritasPrepKarishma wrote:
smartguy595 wrote:
On the 25th of November in 1990, John was trying to make a new plan for Jan 1991. However, he did not have a new calendar that included Jan 1991. Then, in order to match a new plan for Jan 1991, which of following months of 1990 should he look at?

A. March B. April C. May D. June E. July

Can someone explain how to solve this in easy approach!

You need to find the month which will replicate the month of Jan 1991. This will happen when the number of days between the 1st of that month and 1st Jan are a multiple of 7.
Each month has at least 28 days which is a multiple of 7.
Start from July (option (E)) - July has 3 additional days. August has 3. Sep has 2. Oct has 3. Nov has 2. Dec has 3.
3 + 3 + 2 + 3 + 2 + 3 = 16
June has 2 additional days so 16+2 = 18
May has 3 additional days so 18+3 = 21

Starting from May 1, the number of days is a multiple of 7 till Jan 1991 so Jan calendar will mirror the May calendar.

Hi
this question needs one knows about numbers of the months in each month, which is not ordinary for internationals!
is it possible we see such question in real GMAT?
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Re: On the 25th of November in 1990, John was trying to make a new plan fo  [#permalink]

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02 Nov 2017, 21:39
soodia wrote:
VeritasPrepKarishma wrote:
smartguy595 wrote:
On the 25th of November in 1990, John was trying to make a new plan for Jan 1991. However, he did not have a new calendar that included Jan 1991. Then, in order to match a new plan for Jan 1991, which of following months of 1990 should he look at?

A. March B. April C. May D. June E. July

Can someone explain how to solve this in easy approach!

You need to find the month which will replicate the month of Jan 1991. This will happen when the number of days between the 1st of that month and 1st Jan are a multiple of 7.
Each month has at least 28 days which is a multiple of 7.
Start from July (option (E)) - July has 3 additional days. August has 3. Sep has 2. Oct has 3. Nov has 2. Dec has 3.
3 + 3 + 2 + 3 + 2 + 3 = 16
June has 2 additional days so 16+2 = 18
May has 3 additional days so 18+3 = 21

Starting from May 1, the number of days is a multiple of 7 till Jan 1991 so Jan calendar will mirror the May calendar.

Hi
this question needs one knows about numbers of the months in each month, which is not ordinary for internationals!
is it possible we see such question in real GMAT?

You mean that do we need to know the number of days in each month? Yes, it is expected of us to know. The digital world all across follows the same calendar and considering that it is an online exam, knowledge of this calendar is pretty basic.
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Re: On the 25th of November in 1990, John was trying to make a new plan fo  [#permalink]

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06 Mar 2019, 03:56
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Re: On the 25th of November in 1990, John was trying to make a new plan fo   [#permalink] 06 Mar 2019, 03:56
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